Question Detail

How many pieces of 0.85 meteres can be cut from a rod 42.5 meteres long

Answer: Option C

Explanation:

We need so simple divide 42.5/0.85,
=(4250/85) = 50

1. Simplify
\begin{aligned}
16-[5-(6+2(7-\overline{8-5}))]
\end{aligned}

Answer: Option B

Explanation:

\begin{aligned}
= 16-[5-(6+2(7-8+5))]
\end{aligned}
(Please check due to overline, sign has been changed)
\begin{aligned}
= 16-[5-(6+2 \times 4))]
\end{aligned}
\begin{aligned}
= 16-[-9] = 16 + 9 = 25
\end{aligned}

2. In a group of ducks and buffaloes, the total number of legs are 24 more than twice the number of heads. Find the total number of buffaloes.

Answer: Option C

Explanation:

Let the number of buffaloes be x and the number of ducks be y
=> 4x + 2y = 2 (x + y) + 24

=> 2x = 24 => x = 12

3. 7500 + (1250 / 50)

7500
7525
7550
8000

Answer: Option B

Explanation:

As per BODMAS rule first we will solve the terms in the bracket then other.
= 7500 + (25) = 7525

4. 5004 / 139 - 6

Answer: Option D

5. 5.8 * 2.5 + 0.6 * 6.75 + 139.25= ?

157.60
147.80
147.60
157.80

Answer: Option D

Question Detail

How many pieces of 0.85 meteres can be cut from a rod 42.5 meteres long

1. Simplify \begin{aligned} 16-[5-(6+2(7-\overline{8-5}))] \end{aligned}

2. In a group of ducks and buffaloes, the total number of legs are 24 more than twice the number of heads. Find the total number of buffaloes.

3. 7500 + (1250 / 50)

4. 5004 / 139 - 6

5. 5.8 * 2.5 + 0.6 * 6.75 + 139.25= ?

1. Simplify
\begin{aligned}
16-[5-(6+2(7-\overline{8-5}))]
\end{aligned}