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How many minutes does Aditya take to cover a distance of 400 m, if he runs at a speed of 20 km/hr

  • 115min
  • 215min
  • 315min
  • 415min

Answer: Option A

Explanation:

We know that,
Time=DistanceSpeedSpeed=20 km/hr=20∗518m/sec=509m/sec Time =(400∗950)=72sec=115min



Similar Questions :

1. The distance between two cities A and B is 330 Km. A train starts from A at 8 a.m. and travel towards B at 60 km/hr. Another train starts from B at 9 a.m and travels towards A at 75 Km/hr. At what time do they meet?

  • 10 am
  • 11 am
  • 12 pm
  • 1 pm

Answer: Option B

Explanation:

Suppose they meet x hrs after 8 a.m.
then
(Distance moved by first in x hrs) + [Distance moved by second in (x-1) hrs]
= 330
So, 60x+75(x-1) = 330

x=3.

So,they meet at (8+3). i.e 11a.m.

2. A thief is noticed by a policeman from a distance of 200 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. What is the distance between them after 6 minutes ?

  • 50 meter
  • 100 meter
  • 110 meter
  • None of above

Answer: Option B

Explanation:

Relative speed of the thief and policeman = (11 – 10) km/hr = 1 km/hr

Distance covered in 6 minutes =
160∗6=110=100meters



So distance between them after 6 minutes = 200 - 100
= 100 meters

3. A man complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km.

  • 200 Km
  • 222 Km
  • 224 Km
  • 248 Km

Answer: Option C

Explanation:

Let time taken to travel the first half = x hr
Then time taken to travel the second half = (10 - x) hr

Distance covered in the the first half = 21x [because, distance = time*speed]
Distance covered in the the second half = 24(10 - x)

Distance covered in the the first half = Distance covered in the the second half
So,
21x = 24(10 - x)
=> 45x = 240
=> x = 16/3

Total Distance = 2*21(16/3) = 224 Km [multiplied by 2 as 21x was distance of half way]

4. A train covers a distance in 50 minutes, if it runs at a speed of 48kmph on an average. Find the speed at which the train must run to reduce the time of journey to 40 minutes.

  • 50 km/hr
  • 60 km/hr
  • 65 km/hr
  • 70 km/hr

Answer: Option B

Explanation:

We are having time and speed given, so first we will calculate the distance. Then we can get new speed for given time and distance.
Lets solve it.

Time = 50/60 hr = 5/6 hr
Speed = 48 mph
Distance = S*T = 48 * 5/6 = 40 km

New time will be 40 minutes so,
Time = 40/60 hr = 2/3 hr
Now we know,
Speed = Distance/Time
New speed = 40*3/2 kmph = 60kmph

5. A car moves at 80 km/hr. What is the speed of the car in meters per second ?

  • 2029msec
  • 2229msec
  • 2429msec
  • 2629msec

Answer: Option B

Explanation:

Speed=(80∗518)m/sec=2009m/sec=2229msec

Read more from - Time and Distance Questions Answers
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