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Question Detail
From a pack of 52 cards, 1 card is drawn at random. Find the probability of a face card drawn.
- 3/13
- 1/52
- 1/4
- None of above
Answer: Option A
Explanation:
Total number of cases = 52
Total face cards = 12 [favourable cases]
So probability = 12 /52 = 3/13
1. From a pack of 52 cards, 1 card is drawn at random. Find the probability of a face card drawn.
- 3/13
- 1/52
- 1/4
- None of above
Answer: Option A
Explanation:
Total number of cases = 52
Total face cards = 12 [favourable cases]
So probability = 12 /52 = 3/13
2. Three unbiased coins are tossed, what is the probability of getting at least 2 tails ?
- 1/3
- 1/6
- 1/2
- 1/8
Answer: Option C
Explanation:
Total cases are = 2*2*2 = 8, which are as follows
[TTT, HHH, TTH, THT, HTT, THH, HTH, HHT]
Favoured cases are = [TTH, THT, HTT, TTT] = 4
So required probability = 4/8 = 1/2
3. In a throw of coin what is the probability of getting tails.
- 1
- 2
- 1/2
- 0
Answer: Option C
Explanation:
Total cases = [H,T] - 2
Favourable cases = [T] -1
So probability of getting tails = 1/2
4. Two dice are thrown simultaneously. What is the probability of getting two numbers whose product is even ?
- 3/4
- 1/4
- 7/4
- 1/2
Answer: Option A
Explanation:
Total number of cases = 6*6 = 36
Favourable cases = [(1,2),(1,4),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,2),(3,4),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,2),(5,4),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)] = 27
So Probability = 27/36 = 3/4
5. What is the probability of getting a sum 9 from two throws of dice.
- 1/3
- 1/9
- 1/12
- 2/9
Answer: Option B
Explanation:
Total number of cases = 6*6 = 36
Favoured cases = [(3,6), (4,5), (6,3), (5,4)] = 4
So probability = 4/36 = 1/9
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