Find the value of X X = (6/119) * (63/8) * (17/9)

1. How many pieces of 0.85 meteres can be cut from a rod 42.5 meteres long

30
40
50
60

Answer: Option C

Explanation:

We need so simple divide 42.5/0.85,
=(4250/85) = 50

2. Simplify
\begin{aligned}
16-[5-(6+2(7-\overline{8-5}))]
\end{aligned}

23
25
28
30

Answer: Option B

Explanation:

\begin{aligned}
= 16-[5-(6+2(7-8+5))]
\end{aligned}
(Please check due to overline, sign has been changed)
\begin{aligned}
= 16-[5-(6+2 \times 4))]
\end{aligned}
\begin{aligned}
= 16-[-9] = 16 + 9 = 25
\end{aligned}

3. Simplify
(31/10) * (3/10) + (7/5) / 20

0
1
10
100

Answer: Option B

Explanation:

= (31/10) * (3/10) + (7/5) / 20
= (3.1) * (.3) + (1.4) / 20
= 0.93 + 0.07
= 1

4. Company workers decided to raise Rs. 3 lakhs by equal contribution from each. Had they contributed Rs. 50 each extra, the contribution would have been Rs. 3.25 lakhs. How many workers were they?

300
400
500
600

Answer: Option C

Explanation:

N * 50 = (325000 - 300000) = 25000
N = 25000 / 50
= 500

5. (3080 + 6160) / 28

380
350
330
310

Answer: Option C

Explanation:

As per BODMAS rule, first we will solve the equation in bracket then we will go for division
= (9240)/28 = 330

Question Detail

Find the value of X X = (6/119) * (63/8) * (17/9)

1. How many pieces of 0.85 meteres can be cut from a rod 42.5 meteres long

2. Simplify \begin{aligned} 16-[5-(6+2(7-\overline{8-5}))] \end{aligned}

3. Simplify (31/10) * (3/10) + (7/5) / 20

4. Company workers decided to raise Rs. 3 lakhs by equal contribution from each. Had they contributed Rs. 50 each extra, the contribution would have been Rs. 3.25 lakhs. How many workers were they?

5. (3080 + 6160) / 28

Find the value of X
X = (6/119) * (63/8) * (17/9)

2. Simplify
\begin{aligned}
16-[5-(6+2(7-\overline{8-5}))]
\end{aligned}

3. Simplify
(31/10) * (3/10) + (7/5) / 20