Question Detail

Find the value of X
3889 + 12.952 - X = 3854.002

47.95
44.95
43.95
40.95

Answer: Option A

1. Evaluate
\begin{aligned} \frac{10.3 \times 10.3 \times 10.3 + 1}{10.3 \times 10.3 - 10.3 + 1}
\end{aligned}

113
1.13
11.3
113

Answer: Option C

Explanation:

\begin{aligned}
a^3 + b^3 = (a+b)(a^2 + b^2 - ab)
\end{aligned}

\begin{aligned}
= \frac{10.3^3 + 1^3}
{10.3^2 + 1^2 - 10.3 \times 1}
\end{aligned}

\begin{aligned}
= (a+b) = (10.3+1) = 11.3
\end{aligned}

2. What decimal of an hour is a second

.0028
.0027
.0026
.0025

Answer: Option B

Explanation:

1/(60*60) = 1/3600 = .0027

3. Evaluate
\begin{aligned}
\frac{3.6 \times 0.48 \times 2.50}{0.12 \times 0.09 \times 0.5}
\end{aligned}

80
800
8000
80000

Answer: Option B

Explanation:

\begin{aligned}
\frac{3.6 \times 0.48 \times 2.50}{0.12 \times 0.09 \times 0.5}
\end{aligned}

\begin{aligned}
= \frac{36 \times 48 \times 250}{12 \times 9 \times 5} = 800
\end{aligned}

4. What will be the vulgar fraction of 0.75

Answer: Option B

Explanation:

0.75 = 75/100 = 3/4

5. Evaluate 2.5 / .0005

5000
500
50000
50

Answer: Option A

Explanation:

2.5 * 10000 / 5 = 25000/5 = 5000

Question Detail

Find the value of X 3889 + 12.952 - X = 3854.002

1. Evaluate \begin{aligned} \frac{10.3 \times 10.3 \times 10.3 + 1}{10.3 \times 10.3 - 10.3 + 1} \end{aligned}

2. What decimal of an hour is a second

3. Evaluate \begin{aligned} \frac{3.6 \times 0.48 \times 2.50}{0.12 \times 0.09 \times 0.5} \end{aligned}

4. What will be the vulgar fraction of 0.75

5. Evaluate 2.5 / .0005

Find the value of X
3889 + 12.952 - X = 3854.002

1. Evaluate
\begin{aligned} \frac{10.3 \times 10.3 \times 10.3 + 1}{10.3 \times 10.3 - 10.3 + 1}
\end{aligned}

3. Evaluate
\begin{aligned}
\frac{3.6 \times 0.48 \times 2.50}{0.12 \times 0.09 \times 0.5}
\end{aligned}