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Find the unit digit in \begin{aligned}
(544)^{102} + (544)^{103}
\end{aligned}

  • 2
  • 4
  • 0
  • 1

Answer: Option C

Explanation:

Required digit is = \begin{aligned}
(4)^{102} + (4)^{103} \end{aligned}
as \begin{aligned} (4)^2 \end{aligned} gives unit digit 6 so \begin{aligned} (4)^{102} \end{aligned} unit digit is 6 and \begin{aligned} (4)^{103} \end{aligned} unit digit is, unit digit of \begin{aligned} 6 \times 4 \end{aligned}= 4, so answer will be unit digit of 6 + 4 = 0

Similar Questions :

1. A number when divided by 44, gives 432 as quotient and 0 as remainder. What will be the remainder when dividing the same number by 31

  • 5
  • 3
  • 4
  • 6

Answer: Option A

Explanation:

P ÷ 44 = 432

=> P = 432 * 44 = 19008

P / 31 = 19008 / 31 = 613, remainder = 5

2. Simplify 586645 * 9999

  • 5865863355
  • 5665863355
  • 4865863355
  • 4665863355

Answer: Option A

Explanation:

Although it is a simple question, but the trick is to save time in solving this.
Rather than multiplying it we can do as follows:
586645 * (10000 - 1) = 5866450000 - 586645 = 5865863355

3. For the integer n, if n*n*n is odd, then what is true

  • n is odd and n*n is even
  • n*n is odd
  • n is even
  • n*n is odd

Answer: Option A

4. What is the unit digit in
\begin{aligned}
(6324)^{1797} \times (615)^{316} \times (341)^{476}
\end{aligned}

  • 1
  • 5
  • 7
  • 0

Answer: Option D

5. 217 * 217 + 183 * 183

  • 70578
  • 82578
  • 80578
  • 80568

Answer: Option C

Explanation:

\begin{aligned}
\frac {1}{2}\times 2(a^2 + b^2) = \frac {1}{2} \times [(a + b)^2 + (a - b)^2]
\end{aligned}
\begin{aligned}
= \frac {1}{2} \times [(217 + 183)^2 + (217 - 183)^2] = 80578
\end{aligned}

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