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Find the largest number of four digits which is exactly divisible by 27,18,12,15

  • 9700
  • 9710
  • 9720
  • 9730

Answer: Option C

Explanation:

LCM of 27-18-12-15 is 540.
After dividing 9999 by 540 we get 279 remainder.
So answer will be 9999-279 = 9720

Similar Questions :

1. Find the largest number of four digits which is exactly divisible by 27,18,12,15

  • 9700
  • 9710
  • 9720
  • 9730

Answer: Option C

Explanation:

LCM of 27-18-12-15 is 540.
After dividing 9999 by 540 we get 279 remainder.
So answer will be 9999-279 = 9720

2. Reduce \begin{aligned}
\frac{368}{575}
\end{aligned} to the lowest terms.

  • \begin{aligned} \frac{30}{25} \end{aligned}
  • \begin{aligned} \frac{28}{29} \end{aligned}
  • \begin{aligned} \frac{28}{29} \end{aligned}
  • \begin{aligned} \frac{16}{25} \end{aligned}

Answer: Option D

Explanation:

We can do it easily by in two steps
Step1: We get the HCF of 368 and 575 which is 23
Step2: Divide both by 23, we will get the answer 16/25

3. LCM of two numbers is 7700 and HCF is 11. If one number is 308 then other number is

  • 269
  • 285
  • 300
  • 275

Answer: Option D

4. Find the largest number which divides 62,132,237 to leave the same reminder

  • 30
  • 32
  • 35
  • 45

Answer: Option C

Explanation:

Trick is HCF of (237-132), (132-62), (237-62)
= HCF of (70,105,175) = 35

5. Find the greatest number which on dividing 1661 and 2045, leaves a reminder of 10 and 13 respectively

  • 125
  • 127
  • 129
  • 131

Answer: Option B

Explanation:

In this type of question, its obvious we need to calculate the HCF, trick is
HCF of (1661 - 10) and (2045 -13)
= HCF (1651, 2032) = 127

Read more from - HCF and LCM Questions Answers