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Question Detail
Find the largest number of four digits which is exactly divisible by 27,18,12,15
- 9700
- 9710
- 9720
- 9730
Answer: Option C
Explanation:
LCM of 27-18-12-15 is 540.
After dividing 9999 by 540 we get 279 remainder.
So answer will be 9999-279 = 9720
1. Find the HCF of
\begin{aligned}
2^2 \times 3^2 \times 7^2, 2 \times 3^4 \times 7
\end{aligned}
- 128
- 126
- 146
- 434
Answer: Option B
Explanation:
HCF is Highest common factor, so we need to get the common highest factors among given values. So we got
2 * 3*3 * 7
2. If LCM of two number is 693, HCF of two numbers is 11 and one number is 99, then find other
- 34
- 77
- 12
- 45
Answer: Option B
Explanation:
For any this type of question, remember
Product of two numbers = Product of their HCF and LCM
So Other number = \begin{aligned} \frac{693 \times 11}{99} \end{aligned} = 77
3. Find the largest number which divides 62,132,237 to leave the same reminder
- 30
- 32
- 35
- 45
Answer: Option C
Explanation:
Trick is HCF of (237-132), (132-62), (237-62)
= HCF of (70,105,175) = 35
4. If the product of two numbers is 84942 and their H.C.F. is 33, find their L.C.M.
- 2574
- 2500
- 1365
- 1574
Answer: Option A
Explanation:
HCF * LCM = 84942, because we know
Product of two numbers = Product of HCF and LCM
LCM = 84942/33 = 2574
5. Find the greatest number that will divide 400, 435 and 541 leaving 9, 10 and 14 as remainders respectively
- 19
- 17
- 13
- 9
Answer: Option B
Explanation:
Answer will be HCF of (400-9, 435-10, 541-14)
HCF of (391, 425, 527) = 17
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