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Find the HCF of \begin{aligned} \frac{2}{3}, \frac{4}{6}, \frac{8}{27} \end{aligned}

  • \begin{aligned} \frac{2}{27} \end{aligned}
  • \begin{aligned} \frac{8}{3} \end{aligned}
  • \begin{aligned} \frac{2}{3} \end{aligned}
  • \begin{aligned} \frac{8}{27} \end{aligned}

Answer: Option A

Explanation:

Whenever we have to solve this sort of question, remember the formula.
HCF = \begin{aligned} \frac{HCF of Numerators}{LCM of Denominators} \end{aligned}
So answers will be option 1

Similar Questions :

1. Find the HCF of 54, 288, 360

  • 18
  • 36
  • 54
  • 108

Answer: Option A

Explanation:

Lets solve this question by factorization method.

\begin{aligned}
18 = 2 \times 3^2, 288 = 2^5 \times 3^2, 360 = 2^3 \times 3^2 \times 5
\end{aligned}

So HCF will be minimum term present in all three, i.e.
\begin{aligned}
2 \times 3^2 = 18
\end{aligned}

2. The greatest possible length which can be used to measure exactly the lengths 7 m, 3 m 85 cm, 12 m 95 cm is

  • 16cm
  • 25cm
  • 15cm
  • 35cm

Answer: Option D

Explanation:

So by now, you must be knowing this is a question of HCF, right.
H.C.F. of (700 cm, 385 cm, 1295 cm) = 35 cm.

3. If LCM of two number is 693, HCF of two numbers is 11 and one number is 99, then find other

  • 34
  • 77
  • 12
  • 45

Answer: Option B

Explanation:

For any this type of question, remember
Product of two numbers = Product of their HCF and LCM

So Other number = \begin{aligned} \frac{693 \times 11}{99} \end{aligned} = 77

4. LCM of two numbers is 7700 and HCF is 11. If one number is 308 then other number is

  • 269
  • 285
  • 300
  • 275

Answer: Option D

5. Reduce \begin{aligned}
\frac{803}{876}
\end{aligned} to the lowest terms.

  • \begin{aligned} \frac{11}{12} \end{aligned}
  • \begin{aligned} \frac{23}{24} \end{aligned}
  • \begin{aligned} \frac{26}{27} \end{aligned}
  • \begin{aligned} \frac{4}{7} \end{aligned}

Answer: Option A

Explanation:

HCF of 803 and 876 is 73, Divide both by 73, We get the answer 11/12

Read more from - HCF and LCM Questions Answers