Question Detail

Find the HCF of $\begin{aligned} \frac{2}{3}, \frac{4}{6}, \frac{8}{27} \end{aligned}$

$\begin{aligned} \frac{2}{27} \end{aligned}$
$\begin{aligned} \frac{8}{3} \end{aligned}$
$\begin{aligned} \frac{2}{3} \end{aligned}$
$\begin{aligned} \frac{8}{27} \end{aligned}$

Answer: Option A

Explanation:

Whenever we have to solve this sort of question, remember the formula.
HCF = $\begin{aligned} \frac{HCF of Numerators}{LCM of Denominators} \end{aligned}$
So answers will be option 1

1. The H.C.F. and L.C.M. of two numbers are 12 and 5040 respectively If one of the numbers is 144, find the other number

Answer: Option D

Explanation:

Solve this question by using below formula.
Product of 2 numbers = product of their HCF and LCM

144 * x = 12 * 5040

x = (12*5040)/144 = 420

2. Find the LCM of $\begin{aligned} \frac{2}{3}, \frac{4}{6}, \frac{8}{27} \end{aligned}$

$\begin{aligned} \frac{2}{27} \end{aligned}$
$\begin{aligned} \frac{8}{3} \end{aligned}$
$\begin{aligned} \frac{2}{3} \end{aligned}$
$\begin{aligned} \frac{8}{27} \end{aligned}$

Answer: Option B

Explanation:

Whenever we have to solve this sort of question, remember the formula.
LCM = \\begin{aligned} \\frac{HCF of Denominators}{LCM of Numerators} \\end{aligned}
So answers will be option 2,
Please also give attention to the difference in formula of HCF and LCM

3. Reduce $\begin{aligned} \frac{803}{876} \end{aligned}$ to the lowest terms.

$\begin{aligned} \frac{11}{12} \end{aligned}$
$\begin{aligned} \frac{23}{24} \end{aligned}$
$\begin{aligned} \frac{26}{27} \end{aligned}$
$\begin{aligned} \frac{4}{7} \end{aligned}$

Answer: Option A

Explanation:

HCF of 803 and 876 is 73, Divide both by 73, We get the answer 11/12

4. Find the HCF of 2.1, 1.05 and 0.63

0.44
0.64
0.21
None of above

Answer: Option C

Explanation:

To solve this question quickly, first remove decimal by multiplying each term with 100,
Then terms become 210, 105, 63
Then HCF of above terms is 21,
So Answer is 0.21

5. Six bells commence tolling together and toll at the intervals of 2,4,6,8,10,12 seconds resp. In 60 minutes how many times they will toll together.

Answer: Option D

Explanation:

LCM of 2-4-6-8-10-12 is 120 seconds, that is 2 minutes.

Now 60/2 = 30
Adding one bell at the starting it will 30+1 = 31

Nagendra 6 years ago

the answer for this problem is 1/27
not 2/27
manoj 11 years ago

ans 1/27 hoga
aditya 11 years ago

sir answer will be 1/27.
Jonix 11 years ago

Wrong...2/54 agains check please
Jonix 11 years ago

wrong...answer is 2/54 none of this...
Gaib 11 years ago

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