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Question Detail
Find the HCF of 2.1, 1.05 and 0.63
- 0.44
- 0.64
- 0.21
- None of above
Answer: Option C
Explanation:
To solve this question quickly, first remove decimal by multiplying each term with 100,
Then terms become 210, 105, 63
Then HCF of above terms is 21,
So Answer is 0.21
1. Which greatest possible length can be used to measure exactly 15 meter 75 cm, 11 meter 25 cm and 7 meter 65 cm
- 45cm
- 255cm
- 244cm
- 55cm
Answer: Option A
Explanation:
Convert first all terms into cm.
i.e. 1575 cm, 1125cm, 765cm.
Now whenever we need to calculate this type of question, we need to find the HCF. HCF of above terms is 255.
2. Six bells commence tolling together and toll at the intervals of 2,4,6,8,10,12 seconds resp. In 60 minutes how many times they will toll together.
- 15
- 16
- 30
- 31
Answer: Option D
Explanation:
LCM of 2-4-6-8-10-12 is 120 seconds, that is 2 minutes.
Now 60/2 = 30
Adding one bell at the starting it will 30+1 = 31
3. Find the HCF of 54, 288, 360
- 18
- 36
- 54
- 108
Answer: Option A
Explanation:
Lets solve this question by factorization method.
\begin{aligned}
18 = 2 \times 3^2, 288 = 2^5 \times 3^2, 360 = 2^3 \times 3^2 \times 5
\end{aligned}
So HCF will be minimum term present in all three, i.e.
\begin{aligned}
2 \times 3^2 = 18
\end{aligned}
4. The greatest possible length which can be used to measure exactly the lengths 7 m, 3 m 85 cm, 12 m 95 cm is
- 16cm
- 25cm
- 15cm
- 35cm
Answer: Option D
Explanation:
So by now, you must be knowing this is a question of HCF, right.
H.C.F. of (700 cm, 385 cm, 1295 cm) = 35 cm.
5. Reduce \begin{aligned}
\frac{803}{876}
\end{aligned} to the lowest terms.
- \begin{aligned} \frac{11}{12} \end{aligned}
- \begin{aligned} \frac{23}{24} \end{aligned}
- \begin{aligned} \frac{26}{27} \end{aligned}
- \begin{aligned} \frac{4}{7} \end{aligned}
Answer: Option A
Explanation:
HCF of 803 and 876 is 73, Divide both by 73, We get the answer 11/12
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