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Question Detail
Find the compound interest on Rs.16,000 at 20% per annum for 9 months, compounded quarterly
- Rs 2520
- Rs 2521
- Rs 2522
- Rs 2523
Answer: Option C
Explanation:
Please remember, when we have to calculate C.I. quarterly then we apply following formula if n is the number of years
Amount=P(1+R4100)4n
Principal = Rs.16,000;
Time=9 months = 3 quarters;
Rate = 20%, it will be 20/4 = 5%
So lets solve this question now,
Amount=16000(1+5100)3=18522C.I=18522−16000=2522
1. Find the compound interest on Rs. 7500 at 4% per annum for 2 years, compounded annually.
- Rs. 610
- Rs. 612
- Rs. 614
- Rs. 616
Answer: Option B
Explanation:
Amount=[7500×(1+4100)2]=(7500×2625×2625)=8112
So compound interest = (8112 - 7500) = 612
2. A man saves Rs 200 at the end of each year and lends the money at 5% compound interest. How much will it become at the end of 3 years.
- Rs 662
- Rs 662.01
- Rs 662.02
- Rs 662.03
Answer: Option C
Explanation:
=[200(2120×2120×2120)+200(2120×2120)+200(2120)]=662.02
3. What will be the compound interest on Rs. 25000 after 3 years at the rate of 12 % per annum
- Rs 10123.20
- Rs 10123.30
- Rs 10123.40
- Rs 10123.50
Answer: Option A
Explanation:
(25000×(1+12100)3)=>25000×2825×2825×2825=>35123.20
So Compound interest will be 35123.20 - 25000
= Rs 10123.20
4. The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Rs 1. Find the sum
- Rs 600
- Rs 625
- Rs 650
- Rs 675
Answer: Option B
Explanation:
Let the Sum be P
S.I.=P∗4∗2100=2P25C.I.=P(1+4100)2−P=676P625−P=51P625As, C.I. - S.I = 1=>51P625−2P25=1=>51P−50P625=1P=625
5. Albert invested amount of 8000 in a fixed deposit for 2 years at compound interest rate of 5 % per annum. How much Albert will get on the maturity of the fixed deposit.
- Rs. 8510
- Rs. 8620
- Rs. 8730
- Rs. 8820
Answer: Option D
Explanation:
=>(8000×(1+5100)2)=>8000×2120×2120=>8820
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