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Question Detail
Find the average of all numbers between 6 and 34 which are divisible by 5
- 15
- 20
- 25
- 30
Answer: Option B
Explanation:
\begin{aligned}
Average = (\frac{10+15+20+25+30}{5}) = \frac{100}{5} =20
\end{aligned}
1. Average of 10 matches is 32, How many runs one should should score to increase his average by 4 runs.
- 70
- 76
- 78
- 80
Answer: Option B
Explanation:
Average after 11 innings should be 36
So, Required score = (11 * 36) - (10 * 32)
= 396 - 320 = 76
2. The average age of the mother and her six children is 12 years which is reduced by 5 years if the age of the mother is excluded. How old is the mother
- 40
- 41
- 42
- 43
Answer: Option C
3. Average age of boys in a class is 16 years and average age of girls is 15 years, what is the average age of all
- 15.5
- 15
- 16
- Cant be computed
Answer: Option D
Explanation:
As number of girls and boys is not given so result cant be computed
4. When a student weighing 45 kgs left a class, the average weight of the remaining 59 students increased by 200g. What is the average weight of the remaining 59 students
- 55
- 56
- 57
- 58
Answer: Option C
Explanation:
Let the average weight of the 59 students be A.
So the total weight of the 59 of them will be 59*A.
The questions states that when the weight of this student who left is added, the total weight of the class = 59A + 45
When this student is also included, the average weight decreases by 0.2 kgs
\begin{aligned}
\frac{59A + 45}{60} = A - 0.2
\end{aligned}
=> 59A + 45 = 60A - 12
=> 45 + 12 = 60A - 59A
=> A = 57
5. The average score of a cricketer for ten matches is 38.9 runs. If the average for first six matches is 42, then average for last four matches is
- 33.25
- 32.25
- 34.25
- 34.50
Answer: Option C
Explanation:
\begin{aligned}
= \frac{(38.9 \times 10)-(42 \times 6)}{4}
\end{aligned}
\begin{aligned}
= \frac{(1216 - 750)}{4} = 34.25
\end{aligned}
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