Answer: Option C
Answer: Option D
Explanation:
\begin{aligned}
= \sqrt{41 - \sqrt{21 + \sqrt{19 - 3}}}
\end{aligned}
\begin{aligned}
= \sqrt{41 - \sqrt{21 + \sqrt{16}}}
\end{aligned}
\begin{aligned}
= \sqrt{41 - \sqrt{21 + 4}}
\end{aligned}
\begin{aligned}
= \sqrt{41 - \sqrt{25}}
\end{aligned}
\begin{aligned}
= \sqrt{41 - \sqrt{25}}
\end{aligned}
\begin{aligned}
= \sqrt{41 - 5}
\end{aligned}
\begin{aligned}
= \sqrt{36} = 6
\end{aligned}
Answer: Option D
Explanation:
\begin{aligned}
= \sqrt{10+\sqrt{25+\sqrt{108+\sqrt{154+\sqrt{225}}}}}
\end{aligned}
\begin{aligned}
=\sqrt{10+\sqrt{25+\sqrt{108+\sqrt{154+15}}}}
\end{aligned}
\begin{aligned}
=\sqrt{10+\sqrt{25+\sqrt{108+\sqrt{154+15}}}}
\end{aligned}
\begin{aligned}
=\sqrt{10+\sqrt{25+\sqrt{108+\sqrt{169}}}}
\end{aligned}
\begin{aligned}
=\sqrt{10+\sqrt{25+\sqrt{108+13}}}
\end{aligned}
\begin{aligned}
=\sqrt{10+\sqrt{25+\sqrt{121}}}
\end{aligned}
\begin{aligned}
=\sqrt{10+\sqrt{25+11}}
\end{aligned}
\begin{aligned}
=\sqrt{10+\sqrt{36}}
\end{aligned}
\begin{aligned}
=\sqrt{10+6}
\end{aligned}
\begin{aligned}
=\sqrt{16} = 4
\end{aligned}
Answer: Option C
Explanation:
So from the question it is clear that total sum collected was 59.29 rupees.
So total paise are 5929.
\begin{aligned}
\text{Total Members = } \sqrt{5929} \\
= 77
\end{aligned}
Answer: Option D
Explanation:
Tip: Please check the question carefully before answering. As 3a is not under the root we can convert it into a formula , lets evaluate now :
\begin{aligned}
= \sqrt{4a^2 - 4a + 1} + 3a \end{aligned}
\begin{aligned}
= \sqrt{(1)^2 + (2a)^2 - 2x1x2a} + 3a \end{aligned}
\begin{aligned}
= \sqrt{(1-2a)^2} + 3a \end{aligned}
\begin{aligned}
= (1-2a) + 3a \end{aligned}
\begin{aligned}
= (1-2a) + 3a \end{aligned}
\begin{aligned}
= 1 + a = 1 + 0.1039 = 1.1039 \end{aligned}
Answer: Option A
Explanation:
\begin{aligned}
3600 = 2^3 \times 5^2 \times 3^2 \times 2
\end{aligned}
To make it a perfect cube it must be divided by
\begin{aligned}
5^2 \times 3^2 \times 2 = 450
\end{aligned}
