Question Detail

Evaluate
\begin{aligned}
\sqrt{53824}
\end{aligned}

Answer: Option B

1. The largest four digit number which is a perfect cube, is:

7000
8000
9261
9999

Answer: Option C

Explanation:

21*21*21 = 9261

2. Students of a class collected as many paise from each student of class as is the number of students in that class. If total collection is Rs. 59.29, then find the total number of students in the class.

Answer: Option C

Explanation:

So from the question it is clear that total sum collected was 59.29 rupees.
So total paise are 5929.
\begin{aligned}
\text{Total Members = } \sqrt{5929} \\
= 77
\end{aligned}

3. Evaluate
\begin{aligned}
\sqrt{6084}
\end{aligned}

Answer: Option C

4. \begin{aligned} \sqrt{\frac{32.4}{x}} = 2 \end{aligned}

Answer: Option B

5. The least perfect square, which is divisible by each of 21, 36 and 66 is

213414
213424
213434
213444

Answer: Option D

Explanation:

L.C.M. of 21, 36, 66 = 2772

Now, 2772 = 2 x 2 x 3 x 3 x 7 x 11

To make it a perfect square, it must be multiplied by 7 x 11.

So, required number = 2 x 2 x 3 x 3 x 7 x 7 x 11 x 11 = 213444

Question Detail

Evaluate \begin{aligned} \sqrt{53824} \end{aligned}

1. The largest four digit number which is a perfect cube, is:

2. Students of a class collected as many paise from each student of class as is the number of students in that class. If total collection is Rs. 59.29, then find the total number of students in the class.

3. Evaluate \begin{aligned} \sqrt{6084} \end{aligned}

4. \begin{aligned} \sqrt{\frac{32.4}{x}} = 2 \end{aligned}

5. The least perfect square, which is divisible by each of 21, 36 and 66 is

Evaluate
\begin{aligned}
\sqrt{53824}
\end{aligned}

3. Evaluate
\begin{aligned}
\sqrt{6084}
\end{aligned}