Question Detail

Evaluate
\begin{aligned}
\frac{2.39^2 - 1.61^2}{2.39 - 1.61}
\end{aligned}

Answer: Option C

Explanation:

Use following formula to solve it quickly
\begin{aligned}
\frac{a^2-b^2}{a-b}=\frac{(a+b)(a-b)}{(a-b)} = (a+b)
\end{aligned}
= (2.39+1.61) = 4

1. What will be the value of
\begin{aligned}
25.732^2 - 15.732^2
\end{aligned}

214.64
314.64
414.64
412.64

Answer: Option C

Explanation:

Can be easily solved with following formula
\begin{aligned}
a^2 - b^2 = (a - b)(a + b)
\end{aligned}

2. Evaluate
\begin{aligned}
\frac{3.6 \times 0.48 \times 2.50}{0.12 \times 0.09 \times 0.5}
\end{aligned}

80
800
8000
80000

Answer: Option B

Explanation:

\begin{aligned}
\frac{3.6 \times 0.48 \times 2.50}{0.12 \times 0.09 \times 0.5}
\end{aligned}

\begin{aligned}
= \frac{36 \times 48 \times 250}{12 \times 9 \times 5} = 800
\end{aligned}

3. 792.02 + 101.32 - 206.76

676.58
687.58
686.58
586.58

Answer: Option C

4. 0.5 * 0.002 = ?

0.0001
0.01
0.1
0.001

Answer: Option D

5. Value of
\begin{aligned}
0.5\overline{6}
\end{aligned}

\begin{aligned} \frac{51}{99} \end{aligned}
\begin{aligned} \frac{51}{90} \end{aligned}
\begin{aligned} \frac{51}{9} \end{aligned}
\begin{aligned} \frac{510}{99} \end{aligned}

Answer: Option B

Explanation:

\begin{aligned}
0.5\overline{6} = \frac {56 - 5}{90} = \frac {51}{90}
\end{aligned}

Question Detail

Evaluate \begin{aligned} \frac{2.39^2 - 1.61^2}{2.39 - 1.61} \end{aligned}

1. What will be the value of \begin{aligned} 25.732^2 - 15.732^2 \end{aligned}

2. Evaluate \begin{aligned} \frac{3.6 \times 0.48 \times 2.50}{0.12 \times 0.09 \times 0.5} \end{aligned}

3. 792.02 + 101.32 - 206.76

4. 0.5 * 0.002 = ?

5. Value of \begin{aligned} 0.5\overline{6} \end{aligned}

Evaluate
\begin{aligned}
\frac{2.39^2 - 1.61^2}{2.39 - 1.61}
\end{aligned}

1. What will be the value of
\begin{aligned}
25.732^2 - 15.732^2
\end{aligned}

2. Evaluate
\begin{aligned}
\frac{3.6 \times 0.48 \times 2.50}{0.12 \times 0.09 \times 0.5}
\end{aligned}

5. Value of
\begin{aligned}
0.5\overline{6}
\end{aligned}