1. How many litres of pure acid are there in 8 litres of a 20% solution
1.5
1.6
1.7
1.8
Answer: Option B
Explanation:
Question of this type looks a bit typical, but it is too simple, as below...
It will be 8 * 20/100 = 1.6
2. If x% of y is 100 and y% of z is 200, then find the relation between x and z.
z = x
2z = x
z = 2x
None of above
Answer: Option C
Explanation:
It is , y% of z = 2(x% of y)
=> yz/100 = 2xy/100
=> z = 2x
3. The ratio 5:20 expressed as percent equals to
50 %
125 %
25 %
None of above
Answer: Option C
Explanation:
Actually it means 5 is what percent of 20, which can be calculated as,
(5/20)*100 = 5 * 5 = 25
4. Three candidates contested an election and received 1136, 7636 and 11628 votes respectively. What percentage of the total votes did the winning candidate got
55%
56%
57%
58%
Answer: Option C
Explanation:
Total number of votes polled = (1136 + 7636 + 11628) = 20400
So, Required percentage = 11628/20400 * 100 = 57%
5. 2.09 can be expressed in terms of percentage as
2.09%
20.9%
209%
0.209%
Answer: Option C
Explanation:
While calculation in terms of percentage we need to multiply by 100, so
2.09 * 100 = 209.