Question Detail

Evaluate 28% of 450 + 45% of 280

Answer: Option C

Explanation:

= (28/100) * 450 + (45/100) * 280
= 126 + 126 = 252

1. If number x is 10% less than another number y and y is 10% more than 125, then find out the value of x

123.55
123.65
123.75
123.85

Answer: Option C

2. Out of 450 students of a school, 325 play football, 175 play cricket and 50 neither play football nor cricket. How many students play both football and cricket ?

Answer: Option B

Explanation:

Students who play cricket, n(A) = 325
Students who play football, n(B) = 175
Total students who play either or both games,
$\begin{aligned} = n(A\cup B) = 450-50 = 400\\ \text{Required Number}, n(A \cap B) \\ = n(A)+n(B)-n(A\cup B) \\ = 325 + 175 - 400 = 100 \end{aligned}$

3. Rahul's Mathematics test had 75 problems, 10 arithmetic, 30 algebra, 35 geometry problems. Although he answered 70% of arithmetic, 40% of arithmetic and 60% of geometry problems correctly, still he got less than 60% problems right. How many more questions he would have to answer more to get passed

Answer: Option A

Explanation:

Number of questions attempted correctly = (70% of 10 + 40% of 30 + 60% of 35)
= 7 + 12 + 21 = 40.

Questions to be answered correctly for 60% = 60% of total quations
= 60 % of 75 = 45.

He would have to answer 45 - 40 = 5

4. In a hotel, 60% had vegetarian lunch while 30% had non-vegetarian lunch and 15% had both type of lunch. If 96 people were present, how many did not eat either type of lunch ?

Answer: Option D

Explanation:

$\begin{aligned} n(A) = \left(\frac{60}{100}*96\right) = \frac{288}{5} \\ n(B) = \left(\frac{30}{100}*96\right) = \frac{144}{5} \\ n(A\cap B) = \left(\frac{15}{100}*96\right) = \frac{72}{5} \\ \text{People who have either or both lunch} \\ n(A\cup B) = \frac{288}{5}+\frac{144}{5}-\frac{72}{5} \\ = \frac{360}{5} = 72 \end{aligned}$

So People who do no have either lunch were = 96 -72
= 24