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Question Detail
Due to an increase in 30% in the price of eggs, 3 eggs less are available for Rs. 7.80. Find the present rate of eggs per dozen.
- Rs. 9.36
- Rs. 10.36
- Rs. 11.36
- Rs. 12.36
Answer: Option A
Explanation:
Let the original price per egg be Rs x
Then increased price will be,
\begin{aligned}
\left(\frac{130}{100}x\right) \\
=> \frac{7.80}{x}-\frac{7.80}{\frac{130}{100}x} = 3\\
=> \frac{7.80}{x}-\frac{780}{130x} = 3 \\
=> 390x = 234 \\
=> x = 0.6 \\
\text{Actual price was Rs 0.6} \\
\text{Present price per dozen will be} \\
Rs.\left(12*\frac{130}{100}*0.6 \right) \\
= Rs. 9.36
\end{aligned}
1. Two numbers are less than third number by 30% and 37% respectively. How much percent is the second number less than by the first
- 8%
- 9%
- 10%
- 11%
Answer: Option C
Explanation:
Let the third number is x.
then first number = (100-30)% of x
= 70% of x = 7x/10
Second number is (63x/100)
Difference = 7x/10 - 63x/100 = 7x/10
So required percentage is, difference is what percent of first number
=> (7x/100 * 10/7x * 100 )% = 10%
2. If sales tax is reduced from 5% to 4%, then what difference it will make if you purchase an item of Rs. 1000
- 10
- 20
- 30
- 40
Answer: Option A
Explanation:
Clue: Answer will be 5% of 1000 - 4% of 1000
3. If number x is 10% less than another number y and y is 10% more than 125, then find out the value of x
- 123.55
- 123.65
- 123.75
- 123.85
Answer: Option C
4. Total number of boys and girls in a school is 150. If the number of boys is x, then girls become x% of the total number of students. The number of boys is
- 50
- 60
- 70
- 80
Answer: Option B
Explanation:
Clearly,
x% of 150 = 150 - x [as x is number of boys]
\begin{aligned}
=> x + \frac{x}{100} * 150 = 150 \\
=> \frac{5}{2}x = 150 \\
=> x = 60 \\
\end{aligned}
5. Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are
- 42,30
- 42,31
- 42,32
- 42,33
Answer: Option D
Explanation:
Let their marks be (x+9) and x.
Then, x+9 = 56/100(x + 9 +x)
=> 25(x+9)
=> 14 (2x + 9)
=> 3x = 99
=> x = 33.
So, their marks are 42 and 33
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