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Question Detail
\begin{aligned}
\sqrt{41 - \sqrt{21 + \sqrt{19 - \sqrt{9}}}}
\end{aligned}
- 4
- 26
- 16
- 6
Answer: Option D
Explanation:
\begin{aligned}
= \sqrt{41 - \sqrt{21 + \sqrt{19 - 3}}}
\end{aligned}
\begin{aligned}
= \sqrt{41 - \sqrt{21 + \sqrt{16}}}
\end{aligned}
\begin{aligned}
= \sqrt{41 - \sqrt{21 + 4}}
\end{aligned}
\begin{aligned}
= \sqrt{41 - \sqrt{25}}
\end{aligned}
\begin{aligned}
= \sqrt{41 - \sqrt{25}}
\end{aligned}
\begin{aligned}
= \sqrt{41 - 5}
\end{aligned}
\begin{aligned}
= \sqrt{36} = 6
\end{aligned}
1. Evaluate
\begin{aligned}
\sqrt{10+\sqrt{25+\sqrt{108+\sqrt{154+\sqrt{225}}}}}
\end{aligned}
- 16
- 8
- 6
- 4
Answer: Option D
Explanation:
\begin{aligned}
= \sqrt{10+\sqrt{25+\sqrt{108+\sqrt{154+\sqrt{225}}}}}
\end{aligned}
\begin{aligned}
=\sqrt{10+\sqrt{25+\sqrt{108+\sqrt{154+15}}}}
\end{aligned}
\begin{aligned}
=\sqrt{10+\sqrt{25+\sqrt{108+\sqrt{154+15}}}}
\end{aligned}
\begin{aligned}
=\sqrt{10+\sqrt{25+\sqrt{108+\sqrt{169}}}}
\end{aligned}
\begin{aligned}
=\sqrt{10+\sqrt{25+\sqrt{108+13}}}
\end{aligned}
\begin{aligned}
=\sqrt{10+\sqrt{25+\sqrt{121}}}
\end{aligned}
\begin{aligned}
=\sqrt{10+\sqrt{25+11}}
\end{aligned}
\begin{aligned}
=\sqrt{10+\sqrt{36}}
\end{aligned}
\begin{aligned}
=\sqrt{10+6}
\end{aligned}
\begin{aligned}
=\sqrt{16} = 4
\end{aligned}
2. Students of a class collected as many paise from each student of class as is the number of students in that class. If total collection is Rs. 59.29, then find the total number of students in the class.
- 55
- 65
- 77
- 80
Answer: Option C
Explanation:
So from the question it is clear that total sum collected was 59.29 rupees.
So total paise are 5929.
\begin{aligned}
\text{Total Members = } \sqrt{5929} \\
= 77
\end{aligned}
3. \begin{aligned}
(\frac{\sqrt{625}}{11} \times \frac{14}{\sqrt{25}} \times \frac{11}{\sqrt{196}})
\end{aligned}
- 15
- 7
- 5
- 9
Answer: Option C
Explanation:
\begin{aligned}
= (\frac{25}{11} \times \frac{14}{5} \times \frac{11}{14})
\end{aligned}
\begin{aligned}
= 5
\end{aligned}
4. if a = 0.1039, then the value of
\begin{aligned} \sqrt{4a^2 - 4a + 1} + 3a \end{aligned}
- 12.039
- 1.2039
- 11.039
- 1.1039
Answer: Option D
Explanation:
Tip: Please check the question carefully before answering. As 3a is not under the root we can convert it into a formula , lets evaluate now :
\begin{aligned}
= \sqrt{4a^2 - 4a + 1} + 3a \end{aligned}
\begin{aligned}
= \sqrt{(1)^2 + (2a)^2 - 2x1x2a} + 3a \end{aligned}
\begin{aligned}
= \sqrt{(1-2a)^2} + 3a \end{aligned}
\begin{aligned}
= (1-2a) + 3a \end{aligned}
\begin{aligned}
= (1-2a) + 3a \end{aligned}
\begin{aligned}
= 1 + a = 1 + 0.1039 = 1.1039 \end{aligned}
5. Find the value of X
\begin{aligned} \sqrt{81} + \sqrt{0.81} = 10.09 - X \end{aligned}
- 0.019
- 0.19
- 0.9
- 0.109
Answer: Option B
Explanation:
\begin{aligned}
=> \sqrt{81} + \sqrt{0.81} = 10.09 - X
\end{aligned}
\begin{aligned}
=> 9 + 0.9 = 10.09 - X
\end{aligned}
\begin{aligned}
=> X = 10.09 - 9.9 = 0.19
\end{aligned}
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