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Question Detail
Average of all prime numbers between 30 to 50
- 37
- 37.8
- 39
- 39.8
Answer: Option D
Explanation:
Prime numbers between 30 and 50 are:
31, 37, 41, 43, 47
Average of prime numbers between 30 to 50 will be
\begin{aligned}
(\frac{31+37+41+43+47}{5}) = \frac{199}{5} = 39.8
\end{aligned}
1. The average weight of a class of 24 students is 35 kg. If the weight of the teacher be included, the average rises by 400 g. The weight of the teacher is
- 45
- 50
- 55
- 60
Answer: Option A
2. Average of 10 numbers is zero. At most how many numbers may be greater than zero
- 0
- 1
- 5
- 9
Answer: Option D
3. A motorist travel to a place 150 km away at an avearge speed of 50 km/hr and returns ar 30 km/hr.His average speed for the whole jouney in km/hr is
- 36.5 km/hr
- 37.5 km/hr
- 35.5 km/hr
- 34.5 km/hr
Answer: Option B
Explanation:
Average speed will be
\begin{aligned}
\frac{2xy}{x+y} km/hr
= \frac{2(50)(30)}{50+30} km/hr
\end{aligned}
= 37.5 km/hr
4. A batsman makes a score of 87 runs in the 17th match and thus increases his average by 3. Find his average after 17th match
- 36
- 37
- 38
- 39
Answer: Option D
Explanation:
Let the average after 17th match is x
then the average before 17th match is x-3
so 16(x-3) + 87 = 17x
=> x = 87 - 48 = 39
5. Marks of a student were wrongly entered in computer as 83, actual marks of that student were 63. Due to this mistake average marks of whole class got increased by half (1/2). Find the total number of students in that class.
- 25
- 30
- 35
- 40
- 45
Answer: Option D
Explanation:
Suppose total number of students are = X
\begin{aligned}
Total increase = x*\frac{1}{2} = \frac{x}{2} \\
=> \frac{x}{2} = 83-63 = 20 \\
=> x = 40
\end{aligned}
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