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Question Detail
Average of 10 matches is 32, How many runs one should should score to increase his average by 4 runs.
- 70
- 76
- 78
- 80
Answer: Option B
Explanation:
Average after 11 innings should be 36
So, Required score = (11 * 36) - (10 * 32)
= 396 - 320 = 76
1. The average score of a cricketer for ten matches is 38.9 runs. If the average for first six matches is 42, then average for last four matches is
- 33.25
- 32.25
- 34.25
- 34.50
Answer: Option C
Explanation:
\begin{aligned}
= \frac{(38.9 \times 10)-(42 \times 6)}{4}
\end{aligned}
\begin{aligned}
= \frac{(1216 - 750)}{4} = 34.25
\end{aligned}
2. Average of 10 numbers is zero. At most how many numbers may be greater than zero
- 0
- 1
- 5
- 9
Answer: Option D
3. Average of all prime numbers between 30 to 50
- 37
- 37.8
- 39
- 39.8
Answer: Option D
Explanation:
Prime numbers between 30 and 50 are:
31, 37, 41, 43, 47
Average of prime numbers between 30 to 50 will be
\begin{aligned}
(\frac{31+37+41+43+47}{5}) = \frac{199}{5} = 39.8
\end{aligned}
4. Find the sum of first 30 natural numbers
- 470
- 468
- 465
- 463
Answer: Option C
Explanation:
Sum of n natural numbers
\begin{aligned}
= \frac{n(n+1)}{2}
\end{aligned}
\begin{aligned}
= \frac{30(30+1)}{2} = \frac{30(31)}{2} = 465
\end{aligned}
5. A motorist travel to a place 150 km away at an avearge speed of 50 km/hr and returns ar 30 km/hr.His average speed for the whole jouney in km/hr is
- 36.5 km/hr
- 37.5 km/hr
- 35.5 km/hr
- 34.5 km/hr
Answer: Option B
Explanation:
Average speed will be
\begin{aligned}
\frac{2xy}{x+y} km/hr
= \frac{2(50)(30)}{50+30} km/hr
\end{aligned}
= 37.5 km/hr
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