Average age of A and B is 24 years and average age of B, C and D is 22 years. The sum of the ages of A, B, C and D is
90
98
120
Data is not adequate
Answer: Option D
Similar Questions :
1. The ratio between the present ages of P and Q is 6:7. If Q is 4 years old than P, what will be the ratio of the ages of P and Q after 4 years
7:8
7:9
3:8
5:8
Answer: Option A
Explanation:
Let P age and Q age is 6x years and 7x years.
Then 7x - 6x = 4 <=> x = 4
So required ratio will be (6x+4): (7x+4) => 28:32 => 7:8
2. Ten years ago A was half of B in age. If the ratio of their present ages is 3 : 4, what will be the total of their present ages
30
35
37
41
Answer: Option B
Explanation:
Let A's age 10 years ago = x years.
Then, B's age 10 years ago = 2x years.
(x + 10) / (2x+ lO) = 3/4
=> x = 5.
So, the total of their present ages =(x + 10 + 2x + 10)
= (3x + 20) = 35 years.
3. The total age of A and B is 12 years more than the total age of B and C. C is how many year younger than A
11
12
13
14
Answer: Option B
Explanation:
Given that A+B = 12 + B + C
=> A – C = 12 + B – B = 12
=> C is younger than A by 12 years
4. Sachin is younger than Rahul by 7 years. If the ratio of their ages is 7:9, find the age of Sachin
23.5
24.5
12.5
14.5
Answer: Option B
Explanation:
If Rahul age is x, then Sachin age is x-7,
so (x-7)/x = 7/9
=> 9x-63 = 7x
=> 2x = 63
=> x = 31.5
So Sachin age is 31.5 - 7 = 24.5
5. Six years ago, the ratio of the ages of Kunal and Sagar was 6:5, Four years hence, the ratio of their ages will be 11:10. What is Sagar age at present
10 years
12 years
14 years
16 years
Answer: Option D
Explanation:
Let six years ago the age of Kunal and Sagar are 6x and 5x resp.
then,
\begin{aligned}
=> \frac{(6x+6)+4}{(5x+6)+4} = \frac{11}{10}
\end{aligned}
\begin{aligned}
<=> 10(6x+10) = 11(5x+10)
\end{aligned}
\begin{aligned}
<=> 5x = 10 => x = 2
\end{aligned}