Average age of A and B is 24 years and average age of B, C and D is 22 years. The sum of the ages of A, B, C and D is
90
98
120
Data is not adequate
Answer: Option D
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1. Ages of two persons differ by 16 years. If 6 year ago, the elder one be 3 times as old the younger one, find their present age
12,28
14,30
16,32
18,34
Answer: Option B
Explanation:
Let the age of younger person is x,
Then elder person age is (x+16)
=> 3(x-6) = (x+16-6) [6 years before]
=> 3x-18 = x+10
=> x = 14.
So other person age is x + 16 = 30
2. A person's present age is two-fifth of the age of his mother. After 8 years, he will be one-half of the age of his mother. How old is the mother at present
38
40
42
44
Answer: Option B
Explanation:
Let the mother's present age be x years.
Then, the person's present age = (2/5 x) years.
3. Ten years ago A was half of B in age. If the ratio of their present ages is 3 : 4, what will be the total of their present ages
30
35
37
41
Answer: Option B
Explanation:
Let A's age 10 years ago = x years.
Then, B's age 10 years ago = 2x years.
(x + 10) / (2x+ lO) = 3/4
=> x = 5.
So, the total of their present ages =(x + 10 + 2x + 10)
= (3x + 20) = 35 years.
4. Sushil was thrice as old as Snehal 6 years back. Sushil will be times as old as Snehal 6 years hence. How old is Snehal today
12
16
18
24
Answer: Option A
Explanation:
Let Snehals age 6 years back = x.
Then, Sushils age 6 years back = 3x.
(5/3) * (X + 6 + 6) = (3X + 6 + 6)
So 5(x+ 12) = 3(3x+ 12),
so x=6.
Snehal Age = (x+ 6) years = 12 years
5. Ten years ago, P was half of Q in age. If the ratio of their present ages is 3:4, what will be the total of their present ages
35
34
45
25
Answer: Option A
Explanation:
Let the present age of P and Q be 3x and 4x respectively.
Ten years ago, P was half of Q in age
=> 2(3x – 10) = (4x – 10)
