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Question Detail
Average age of A and B is 24 years and average age of B, C and D is 22 years. The sum of the ages of A, B, C and D is
- 90
- 98
- 120
- Data is not adequate
Answer: Option D
1. Total of the ages of A, B ahd C at present is 90 years. Ten years ago, the ratio of their ages was 1: 2: 3. What is the age of B at present
- 25
- 30
- 45
- 60
Answer: Option B
Explanation:
Let their ages 10 years ago is x, 2x and 3x years.
10 + 2x + 10 + 3x + 10 = 90 hence x= 10
B’s present age = (2x + 10) =30 years
2. A person's present age is two-fifth of the age of his mother. After 8 years, he will be one-half of the age of his mother. How old is the mother at present
- 38
- 40
- 42
- 44
Answer: Option B
Explanation:
Let the mother's present age be x years.
Then, the person's present age = (2/5 x) years.
=> (2/5 x + 8/2) = 1 (x + 8)
=> 2(2x + 40) = 5(x + 8)
=> x = 40
3. The sum of the present ages of a father and his son is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, son's age will be
- 15 years
- 18 years
- 20 years
- 22 years
Answer: Option C
Explanation:
Clue : (60 - x) - 6 = 5(x - 6)
4. The ages of two persons differ by 20 years. If 5 years ago, the elder one be 5 times as old as the younger one, their present ages (in years) are respectively
- 20,20
- 20,10
- 25,15
- 30,10
Answer: Option D
Explanation:
Let their ages be x and (x + 20) years.
5 (x - 5) = (x + 20 - 5) or 4x = 40 or x = 10.
Their present ages are 30 years and 10 years
5. Sachin is younger than Rahul by 7 years. If the ratio of their ages is 7:9, find the age of Sachin
- 23.5
- 24.5
- 12.5
- 14.5
Answer: Option B
Explanation:
If Rahul age is x, then Sachin age is x-7,
so (x-7)/x = 7/9
=> 9x-63 = 7x
=> 2x = 63
=> x = 31.5
So Sachin age is 31.5 - 7 = 24.5
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