Question Detail

Along a yard 225 metres long, 26 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between two consecutive trees

Answer: Option B

Explanation:

26 trees have 25 gaps between them,
Required distance (225/25) = 10

1. Simplify
\begin{aligned} 1+\frac{1}{2}+\frac{1}{4}+\frac{1}{7}+\frac{1}{14}+\frac{1}{28} = ? \end{aligned}

Answer: Option A

Explanation:

By taking LCM we get
=\begin{aligned} \frac{28+14+7+4+2+1}{28}
= \frac{56}{28} = 2\end{aligned}

2. In a class free notebooks were distributed among all the children. Each child got notebooks which were one-eighth of the number of children. If number of children been half, then each child would have recieved 16 notebooks in total. Find the total number of books distributed.

Answer: Option B

Explanation:

Let suppose total number of students in class are X.
Then from the question we can conclude it that,
\begin{aligned}
X*\frac{1}{8}X = \frac{X}{2}*16 \\
=> X = 64\\
\text{Total notebooks,} \\
= \frac{1}{8}X^2 \\
= \left( \frac{1}{8} * 64 * 64 \right) \\
= 512
\end{aligned}

3. \begin{aligned}
(3\frac{1}{4}\div \{1\frac{1}{4} - \frac{1}{2}(2\frac{1}{2} - \overline {\frac{1}{4} - \frac{1}{6}} ) \} )
\end{aligned}

Answer: Option A

Explanation:

Tip:
As you can see, there is bar over
\begin{aligned}
\overline{\frac{1}{4}-\frac{1}{6}}
\end{aligned}
So their sign will be changed from - to + as
\begin{aligned}
\frac{1}{4}+\frac{1}{6}
\end{aligned}

4. Simplify
\begin{aligned} 1\frac{3}{4}+5\frac{1}{3}+3\frac{2}{5} \end{aligned}

\begin{aligned}10\frac{29}{60} \end{aligned}
\begin{aligned}8\frac{29}{60} \end{aligned}
\begin{aligned}6\frac{29}{60} \end{aligned}
\begin{aligned}4\frac{29}{60} \end{aligned}

Answer: Option A

Explanation:

\begin{aligned} = \frac{7}{4}+\frac{16}{3}+\frac{17}{5} \end{aligned}

\begin{aligned} = \frac{105+320+204}{60}
\end{aligned}
\begin{aligned} = \frac{629}{60}
\end{aligned}
\begin{aligned} = 10\frac{29}{60}
\end{aligned}

5. Along a yard 225 metres long, 26 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between two consecutive trees

Answer: Option B

Explanation:

26 trees have 25 gaps between them,
Required distance (225/25) = 10

Question Detail

Along a yard 225 metres long, 26 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between two consecutive trees

1. Simplify \begin{aligned} 1+\frac{1}{2}+\frac{1}{4}+\frac{1}{7}+\frac{1}{14}+\frac{1}{28} = ? \end{aligned}

2. In a class free notebooks were distributed among all the children. Each child got notebooks which were one-eighth of the number of children. If number of children been half, then each child would have recieved 16 notebooks in total. Find the total number of books distributed.

3. \begin{aligned} (3\frac{1}{4}\div \{1\frac{1}{4} - \frac{1}{2}(2\frac{1}{2} - \overline {\frac{1}{4} - \frac{1}{6}} ) \} ) \end{aligned}

4. Simplify \begin{aligned} 1\frac{3}{4}+5\frac{1}{3}+3\frac{2}{5} \end{aligned}

5. Along a yard 225 metres long, 26 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between two consecutive trees

1. Simplify
\begin{aligned} 1+\frac{1}{2}+\frac{1}{4}+\frac{1}{7}+\frac{1}{14}+\frac{1}{28} = ? \end{aligned}

3. \begin{aligned}
(3\frac{1}{4}\div \{1\frac{1}{4} - \frac{1}{2}(2\frac{1}{2} - \overline {\frac{1}{4} - \frac{1}{6}} ) \} )
\end{aligned}

4. Simplify
\begin{aligned} 1\frac{3}{4}+5\frac{1}{3}+3\frac{2}{5} \end{aligned}