Along a yard 225 metres long, 26 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between two consecutive trees

Answer: Option A

Explanation:

$$\begin{aligned} = \frac{7}{4}+\frac{16}{3}+\frac{17}{5} \end{aligned}$$

$$\begin{aligned} = \frac{105+320+204}{60} \end{aligned}$$
$$\begin{aligned} = \frac{629}{60} \end{aligned}$$
$$\begin{aligned} = 10\frac{29}{60} \end{aligned}$$

Answer: Option A

Explanation:

$$\begin{aligned} => \frac{4}{7}x + \frac{4}{7} = \frac{15}{4} \end{aligned}$$
$$\begin{aligned} = \frac{4}{7}x = \frac{15}{4} - \frac{4}{7} \end{aligned}$$
$$\begin{aligned} = \frac{4}{7}x = \frac{7}{14} \end{aligned}$$
$$\begin{aligned} = x = \frac{1}{2}\times \frac{7}{4} = \frac{7}{8} \end{aligned}$$

Answer: Option B

Explanation:

18800 / 470 / 20 = (18800 / 470) / 20 = 40 / 20 = 2

Answer: Option B

Explanation:

= (31/10) * (3/10) + (7/5) / 20
= (3.1) * (.3) + (1.4) / 20
= 0.93 + 0.07
= 1

Answer: Option C

Explanation:

$$\begin{aligned} \frac{\frac{7}{2}\div {\frac{5}{2}} \times {\frac{3}{2}} }{\frac{7}{2} \div { \frac{5}{2}} of \frac{3}{2} }\div 5.25 \end{aligned}$$

$$\begin{aligned} = \frac{\frac{7}{2}\times {\frac{2}{5}} \times {\frac{3}{2}} }{\frac{7}{2} \div { \frac{15}{4}}}\div 5.25 \end{aligned}$$

$$\begin{aligned} = \frac{\frac{21}{10}} {\frac{7}{2} \times { \frac{4}{15}}}\div {\frac{525}{100}} \end{aligned}$$

$$\begin{aligned} = \frac{21}{10}\times{\frac{15}{14}}\times\frac{100}{525} = \frac{6}{14} = \frac{3}{7} \end{aligned}$$