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Question Detail
Along a yard 225 metres long, 26 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between two consecutive trees
- 8
- 9
- 10
- 11
Answer: Option B
Explanation:
26 trees have 25 gaps between them,
Required distance (225/25) = 10
1. 100 + 50 * 2 = ?
- 200
- 150
- 100
- 300
Answer: Option A
Explanation:
After applying BOMAS rule,
First Multiplication will be done then addition
So it will be 100 + 100 = 200
2. \begin{aligned} 3034 -(1002 \div 20.04) = ? \end{aligned}
- 1964
- 1984
- 2964
- 2984
Answer: Option D
Explanation:
\begin{aligned}
= 3034 -( \frac{1002}{2004} \times 100)
\end{aligned}
\begin{aligned}
= 3034 - 50 = 2984
\end{aligned}
3. \begin{aligned}
(3\frac{1}{4}\div \{1\frac{1}{4} - \frac{1}{2}(2\frac{1}{2} - \overline {\frac{1}{4} - \frac{1}{6}} ) \} )
\end{aligned}
- 78
- 88
- 98
- 108
Answer: Option A
Explanation:
Tip:
As you can see, there is bar over
\begin{aligned}
\overline{\frac{1}{4}-\frac{1}{6}}
\end{aligned}
So their sign will be changed from - to + as
\begin{aligned}
\frac{1}{4}+\frac{1}{6}
\end{aligned}
4. Company workers decided to raise Rs. 3 lakhs by equal contribution from each. Had they contributed Rs. 50 each extra, the contribution would have been Rs. 3.25 lakhs. How many workers were they?
- 300
- 400
- 500
- 600
Answer: Option C
Explanation:
N * 50 = (325000 - 300000) = 25000
N = 25000 / 50
= 500
5. Simplify
(31/10) * (3/10) + (7/5) / 20
- 0
- 1
- 10
- 100
Answer: Option B
Explanation:
= (31/10) * (3/10) + (7/5) / 20
= (3.1) * (.3) + (1.4) / 20
= 0.93 + 0.07
= 1
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