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Question Detail
Along a yard 225 metres long, 26 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between two consecutive trees
- 8
- 9
- 10
- 11
Answer: Option B
Explanation:
26 trees have 25 gaps between them,
Required distance (225/25) = 10
1. If p - q = 3 and
\begin{aligned} p^2 + q^2 = 29 \end{aligned}, find the value of pq.
- 7
- 8
- 9
- 10
Answer: Option D
Explanation:
We know
\begin{aligned} 2ab = (a^2 + b^2) - (a - b)^2 \end{aligned}
\begin{aligned} 2pq = 29 - 9 = 20 \end{aligned}
\begin{aligned} =>pq = 10 \end{aligned}
2. What fraction of \begin{aligned} \frac{4}{7}\end{aligned} should be added to itself to become \begin{aligned} 1\frac{1}{14} \end{aligned}
- \begin{aligned} \frac{7}{8} \end{aligned}
- \begin{aligned} \frac{7}{9} \end{aligned}
- \begin{aligned} \frac{7}{10} \end{aligned}
- \begin{aligned} \frac{7}{11} \end{aligned}
Answer: Option A
Explanation:
\begin{aligned}
=> \frac{4}{7}x + \frac{4}{7} = \frac{15}{4}
\end{aligned}
\begin{aligned}
= \frac{4}{7}x = \frac{15}{4} - \frac{4}{7}
\end{aligned}
\begin{aligned}
= \frac{4}{7}x = \frac{7}{14}
\end{aligned}
\begin{aligned}
= x = \frac{1}{2}\times \frac{7}{4} = \frac{7}{8}
\end{aligned}
3. The number of girls in a class are 7 times the number of boys, which value can never be the of total students
- 40
- 48
- 24
- 30
Answer: Option D
Explanation:
Let the boys are X, then girls are 7X, total = X+7X = 8X
So it should be multiple of 8, 30 is not a multiple of 8.
4. In a group of ducks and buffaloes, the total number of legs are 24 more than twice the number of heads. Find the total number of buffaloes.
- 8
- 10
- 12
- 14
Answer: Option C
Explanation:
Let the number of buffaloes be x and the number of ducks be y
=> 4x + 2y = 2 (x + y) + 24
=> 2x = 24 => x = 12
5. \begin{aligned}
(3\frac{1}{4}\div \{1\frac{1}{4} - \frac{1}{2}(2\frac{1}{2} - \overline {\frac{1}{4} - \frac{1}{6}} ) \} )
\end{aligned}
- 78
- 88
- 98
- 108
Answer: Option A
Explanation:
Tip:
As you can see, there is bar over
\begin{aligned}
\overline{\frac{1}{4}-\frac{1}{6}}
\end{aligned}
So their sign will be changed from - to + as
\begin{aligned}
\frac{1}{4}+\frac{1}{6}
\end{aligned}
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