Question Detail

Alfred buys an old scooter for Rs. 4700 and spends Rs. 800 on its repairs. If he sells the scooter for Rs. 5800, his gain percent is

\begin{aligned} \frac{6}{19}\% \end{aligned}
\begin{aligned} \frac{6}{17}\% \end{aligned}
\begin{aligned} 5\frac{5}{11}\% \end{aligned}
\begin{aligned} 3\frac{5}{11}\% \end{aligned}

Answer: Option C

Explanation:

Whenever we get this type of question, we should have formula in mind that,
Gain% = (gain/cost)*100

Cost = 4700 + 800 = Rs. 5500
S.P. = Rs. 5800

Profit = 5800 - 5500 = 300
\begin{aligned}
Gain\% = \frac{300}{5500}*100 \\
= 5\frac{5}{11}\%
\end{aligned}

1. A fruit seller sells mangoes at the rate of Rs.9 per kg and thereby loses 20%. At what price per kg, he should have sold them to make a profit of 5%

Rs 8.81
Rs 9.81
Rs 10.81
Rs 11.81

Answer: Option D

Explanation:

85 : 9 = 105 : x
x= (9×105/85)
= Rs 11.81

2. A shopkeeper cheats to the extent of 10% while buying and selling, by using false weights. His total gain is.

Answer: Option B

Explanation:

\begin{aligned}
Gain\% = \\ \left( \frac{(100 + \text{common gain}\%)^2}{100} - 100 \right)\% \\
= \left( \frac{(100 + 10)^2}{100} - 100 \right)\% \\
= \left( \frac{12100 - 10000}{100}\right)\% \\
= 21\%

\end{aligned}

3. Akhil purchased 70kg vegetable at Rs. 420, then sold them at the rate of Rs. 6.50 per kg, find the profit percent.

\begin{aligned} 8\frac{1}{3}\% \end{aligned}
\begin{aligned} 7\frac{1}{3}\% \end{aligned}
\begin{aligned} 6\frac{1}{3}\% \end{aligned}
\begin{aligned} 5\frac{1}{3}\% \end{aligned}

Answer: Option A

Explanation:

Please note in this type of questions, get the value of 1 kg to solve this question, lets solve it.

C.P. of 1 Kg = 420/70 = Rs. 6
Selling Price = 6.50
Gain = Rs. 0.50

\begin{aligned}
Gain\% = \frac{.50}{6}*100 \\
= 8\frac{1}{3}\%
\end{aligned}

4. A shopkeeper sells a transistor at Rs. 840 at a gain of 20% and another for Rs. 960 at the loss of 4%. Find his total gain percent.

\begin{aligned} 5\frac{12}{17}\% \end{aligned}
\begin{aligned} 5\frac{13}{17}\% \end{aligned}
\begin{aligned} 5\frac{14}{17}\% \end{aligned}
\begin{aligned} 5\frac{15}{17}\% \end{aligned}

Answer: Option D

Explanation:

In this type of question, we will first find total C.P. of items, then total S.P. of items, then we will get gain or loss. From which we can easily calculate its percentage.

So lets solve it now.
\begin{aligned}
\text{So, C.P. of 1st transistor = }\\
\left( \frac{100}{120} * 840 \right) = 700 \\

\text{C.P. of 2nd transistor = }\\
\left( \frac{100}{96} * 960 \right) = 1000 \\

\text{Total C.P. = 1700 }\\
\text{Total S.P. = 1800 }\\
\text{Gain = 1800 - 1700 = 100}\\
\text{Gain% = } \left( \frac{100}{1700} * 100 \right) \\
= 5\frac{15}{17}\%
\end{aligned}

5. The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, find out the value of x

Answer: Option D

Explanation:

Let the Cost Price of one article = Rs. 1
CP of x articles = Rs. x
CP of 20 articles = 20
Selling price of x articles = 20

Profit = 25% [Given]

\begin{aligned}
\Rightarrow \left (\dfrac{SP - CP }{CP}\right ) = \dfrac{25}{100} = \dfrac{1}{4}

& \Rightarrow \dfrac{\left(20-x \right )}{x} = \dfrac{1}{4} \\
& \Rightarrow 80 - 4x = x \\
& \Rightarrow 5x = 80 \nonumber \\
& \Rightarrow x = \dfrac{80}{5} = 16 \\

\end{aligned}