Question Detail
Ages of two persons differ by 16 years. If 6 year ago, the elder one be 3 times as old the younger one, find their present age
- 12,28
- 14,30
- 16,32
- 18,34
Answer: Option B
Explanation:
Let the age of younger person is x,
Then elder person age is (x+16)
=> 3(x-6) = (x+16-6) [6 years before]
=> 3x-18 = x+10
=> x = 14.
So other person age is x + 16 = 30