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A train running at the speed of 60 km/hr crosses a pole in 9 seconds. Find the length of the train.

  • 150 meter
  • 145 meter
  • 140 meter
  • 135 meter

Answer: Option A

Explanation:

Speed = 60*(5/18) m/sec = 50/3 m/sec

Length of Train(Distance) = Speed * Time

=503∗9=150meter

Similar Questions :

1. A train is 100 meter long and is running at the speed of 30 km per hour. Find the time it will take to pass a man standing at a crossing.

  • 10 seconds
  • 12 seconds
  • 14 seconds
  • 16 seconds

Answer: Option B

Explanation:

As we need to get answer in seconds, so never forget to convert speed into meter per second.

Speed = 30 km/hr = 30* 5/18 m/sec
= 25/3 m/sec

Distance = length of train = 100 meter

Required time =
DistanceSpeed=100253=100∗325=12sec

2. How many seconds will a 500 meter long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr

  • 25 Seconds
  • 28 Seconds
  • 30 Seconds
  • 35 Seconds

Answer: Option C

Explanation:

Relative Speed = 63-3 = 60 Km/hr
= 60 *(5/18) = 50/3 m/sec

Time taken to pass the man will ne
500∗350=30 seconds

3. Speed of a goods train is 72 km/hr. This train crosses a 250 meter platform in 26 seconds. Then find the length of goods train.

  • 250 meters
  • 260 meters
  • 270 meters
  • 280 meters

Answer: Option C

Explanation:

First convert speed from km/hr to m/sec

So, Speed = 72*(5/18) = 20 m/sec
Time = 26 seconds

Let the length of the train be x meters.
We know, Distance = Speed*Time.
[you can remember this formula as remembering DUST = D*ST... Distance=Speed*Time]

x+250 = 20*26
=> x = 270 meters

So length of the goods train is 270 meter

4. A 300 meter long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform.

  • 310 meter
  • 335 meter
  • 345 meter
  • 350 meter

Answer: Option D

Explanation:

Speed = Distance/time = 300/18 = 50/3 m/sec

Let the length of the platform be x meters
then
Distance=Speed∗Timex+300=503∗39=>3(x+300)=1950=>x=350 meters

5. Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is ?

  • 40 meter
  • 45 meter
  • 50 meter
  • 55 meter

Answer: Option C

Explanation:

Let the length of each train is x meter
Distance will be x+x = 2x

Relative Speed = 46-36 = 10 km/hr
= 10*(5/18) = 25/9 m/sec

Distance = Speed*Time

2x=259∗362x=100=>x=50


So length of both the trains are 50 meters

Read more from - Problems on Trains Questions Answers
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