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Question Detail
A sum of Rs 12,500 amounts to Rs. 15,500 in the 4 years at the rate of simple interest. Find the rate percent
- 6 %
- 7 %
- 8 %
- 9 %
Answer: Option A
Explanation:
\begin{aligned}
\text{S.I.} = \frac{P*R*T}{100} \\
=> R = \frac{S.I. * 100}{P*T}
\end{aligned}
So, S.I = 15500 - 12500 = 3000.
\begin{aligned}
=> R = \frac{3000 * 100}{12500*4} = 6\%
\end{aligned}
1. At what rate percent per annum will the simple interest on a sum of money be 2/5 of the amount in 10 years
- 1%
- 2%
- 3%
- 4%
Answer: Option D
Explanation:
Let sum = x
Time = 10 years.
S.I = 2x /5, [as per question]
Rate =( (100 * 2x) / (x*5*10))%
=> Rate = 4%
2. Find the rate at Simple interest, at which a sum becomes four times of itself in 15 years.
- 10%
- 20%
- 30%
- 40%
Answer: Option B
Explanation:
Let sum be x and rate be r%
then, (x*r*15)/100 = 3x [important to note here is that simple interest will be 3x not 4x, beause 3x+x = 4x]
=> r = 20%
3. At 5% per annum simple interest, Rahul borrowed Rs. 500. What amount will he pay to clear the debt after 4 years
- 750
- 700
- 650
- 600
Answer: Option D
Explanation:
We need to calculate the total amount to be paid by him after 4 years, So it will be Principal + simple interest.
So,
\begin{aligned}
=> 500 + \frac{500*5*4}{100}
=> Rs. 600
\end{aligned}
4. Reema took a loan of Rs 1200 with simple interest for as many years as the rate of interest. If she paid Rs. 432 as interest at the end of the loan period, what was the rate of interest.
- 5%
- 6%
- 7%
- 8%
Answer: Option B
Explanation:
Let rate = R% then Time = R years.
\begin{aligned}
=> \frac{1200*R*R}{100}=432 \\
=> R^2 = 36 \\
=> R = 6\%
\end{aligned}
5. A sum of Rs 12,500 amounts to Rs. 15,500 in the 4 years at the rate of simple interest. Find the rate percent
- 6 %
- 7 %
- 8 %
- 9 %
Answer: Option A
Explanation:
\begin{aligned}
\text{S.I.} = \frac{P*R*T}{100} \\
=> R = \frac{S.I. * 100}{P*T}
\end{aligned}
So, S.I = 15500 - 12500 = 3000.
\begin{aligned}
=> R = \frac{3000 * 100}{12500*4} = 6\%
\end{aligned}
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