Question Detail
A sum of money invested at compound interest to Rs. 800 in 3 years and to Rs 840 in 4 years. The rate on interest per annum is.
- 4%
- 5%
- 6%
- 7%
Answer: Option B
Explanation:
S.I. on Rs 800 for 1 year = 40
Rate = (100*40)/(800*1) = 5%
1. We need to divide Total Sum Rs. 3364 between Ram and Sham so that Ram's share at the end of 5 years may equal to Sham's share at the end of seven years with compound interest rate at 5 percent.
- 1864 and 1500
- 1764 and 1600
- 1664 and 1700
- 1564 and 1800
Answer: Option B
Explanation:
It is clear from question that Ram's share after five years = Sham's share after seven years
Hence we can conclude following :
\begin{aligned}
\text{(Rams's present share)}\left(1 + \dfrac{5}{100}\right)^5 = \text{(Sham's present share)}\left(1 + \dfrac{5}{100}\right)^7\\
=> \dfrac{\text{(Ram's present share)}}{\text{(Sham's present share)}}= \dfrac{\left(1 + \dfrac{5}{100}\right)^7}{\left(1 + \dfrac{5}{100}\right)^5} \\ = \left(1 + \dfrac{5}{100}\right)^{(7-5)} = \left(1 + \dfrac{5}{100}\right)^2 \\ = \left(\dfrac{21}{20}\right)^2 = \dfrac{441}{400}
\end{aligned}
Ram's present share : B's present share = 441 : 400
\begin{aligned}
\text{As amount is Rs.3364, Ram's share = }3364 \times \dfrac{441}{(441+400)} \\\\
= 3364 \times \dfrac{441}{841} = 4 \times 441 = \text{ Rs. 1764}
\end{aligned}
So Sham's share is = 3364-1764 = 1600
2. What will be the compound interest on Rs. 25000 after 3 years at the rate of 12 % per annum
- Rs 10123.20
- Rs 10123.30
- Rs 10123.40
- Rs 10123.50
Answer: Option A
Explanation:
\begin{aligned}
(25000 \times (1 + \frac{12}{100})^3) \\
=> 25000\times\frac{28}{25}\times\frac{28}{25}\times\frac{28}{25} \\
=> 35123.20 \\
\end{aligned}
So Compound interest will be 35123.20 - 25000
= Rs 10123.20
3. Albert invested amount of 8000 in a fixed deposit for 2 years at compound interest rate of 5 % per annum. How much Albert will get on the maturity of the fixed deposit.
- Rs. 8510
- Rs. 8620
- Rs. 8730
- Rs. 8820
Answer: Option D
Explanation:
\begin{aligned}
=> (8000 \times(1+\frac{5}{100})^2) \\
=> 8000 \times \frac{21}{20}\times \frac{21}{20} \\
=> 8820
\end{aligned}
4. A man saves Rs 200 at the end of each year and lends the money at 5% compound interest. How much will it become at the end of 3 years.
- Rs 662
- Rs 662.01
- Rs 662.02
- Rs 662.03
Answer: Option C
Explanation:
\begin{aligned}
[200(1+\frac{5}{100})^3 + 200(1+\frac{5}{100})^2+ \\ 200(1+\frac{5}{100})]
= [200(\frac{21}{20} \times \frac{21}{20} \times \frac{21}{20})\\
+ 200(\frac{21}{20}\times\frac{21}{20})+200(\frac{21}{20})] \\
= 662.02
\end{aligned}
5. What will be the difference between simple and compound interest @ 10% per annum on the sum of Rs 1000 after 4 years
- Rs 62.10
- Rs 63.10
- Rs 64.10
- Rs 65.10
Answer: Option C
Explanation:
\begin{aligned}
S.I. = \frac{1000*10*4}{100} = 400 \\
C.I. = [1000(1+\frac{10}{100})^4 - 1000] \\
= 464.10
\end{aligned}
So difference between simple interest and compound interest will be 464.10 - 400 = 64.10