Question Detail
A student got twice as many sums wrong as he got right. If he attempted 48 sums in all, how many did he solve correctly ?
- 12
- 16
- 24
- 18
Answer: Option B
Explanation:
Suppose boy got x sums right and 2x sums wrong,
then,
x+2x = 48
=> 3x = 48
=> x = 16