Question Detail

A shopkeeper expects a gain of 45/2 % on his C.P. If his sale was Rs. 392, then find his profit.

Rs. 70
Rs. 72
Rs. 74
Rs. 76

Answer: Option B

Explanation:

We Know,

\begin{aligned}
S.P. = \left( \frac{100+gain\%}{100} * C.P \right)\\
=> C.P. = \frac{100}{122.50}* 392 \\
= 320 \\

Profit = 392 -320 = Rs 72
\end{aligned}

1. A material is purchased for Rs. 600. If one fourth of the material is sold at a loss of 20% and the remaining at a gain of 10%, Find out the overall gain or loss percentage

\begin{aligned} 4\frac{1}{2} \end{aligned}
\begin{aligned} 3\frac{1}{2} \end{aligned}
\begin{aligned} 2\frac{1}{2} \end{aligned}
\begin{aligned} 1\frac{1}{2} \end{aligned}

Answer: Option C

Explanation:

We need to get the Total selling price to solve this question. Because after getting selling price we can get profit or loss, then we can calculate profit% or loss%

So lets solve this:

Price Received by selling one fourth of the material at a loss of 20% =
(1/4) * 600 * (80/100) = Rs. 120

Price Received by remaining material at a gain of 10% =
(3/4) * 600 * (110/100) = Rs. 495 [Note: 1-(1/4) = 3/4]

Total Selling Price = 120 + 465 = Rs. 615

Profit = 615 - 600 = 15

\begin{aligned}
Profit\% = \left( \frac{Gain}{Cost} * 100 \right)\% \\
= \left( \frac{15}{600} * 100 \right)\% \\
= \frac{5}{2}\% = 2\frac{1}{2}\%
\end{aligned}

2. A shopkeeper sells a transistor at Rs. 840 at a gain of 20% and another for Rs. 960 at the loss of 4%. Find his total gain percent.

\begin{aligned} 5\frac{12}{17}\% \end{aligned}
\begin{aligned} 5\frac{13}{17}\% \end{aligned}
\begin{aligned} 5\frac{14}{17}\% \end{aligned}
\begin{aligned} 5\frac{15}{17}\% \end{aligned}

Answer: Option D

Explanation:

In this type of question, we will first find total C.P. of items, then total S.P. of items, then we will get gain or loss. From which we can easily calculate its percentage.

So lets solve it now.
\begin{aligned}
\text{So, C.P. of 1st transistor = }\\
\left( \frac{100}{120} * 840 \right) = 700 \\

\text{C.P. of 2nd transistor = }\\
\left( \frac{100}{96} * 960 \right) = 1000 \\

\text{Total C.P. = 1700 }\\
\text{Total S.P. = 1800 }\\
\text{Gain = 1800 - 1700 = 100}\\
\text{Gain% = } \left( \frac{100}{1700} * 100 \right) \\
= 5\frac{15}{17}\%
\end{aligned}

3. The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, find out the value of x

Answer: Option D

Explanation:

Let the Cost Price of one article = Rs. 1
CP of x articles = Rs. x
CP of 20 articles = 20
Selling price of x articles = 20

Profit = 25% [Given]

\begin{aligned}
\Rightarrow \left (\dfrac{SP - CP }{CP}\right ) = \dfrac{25}{100} = \dfrac{1}{4}

& \Rightarrow \dfrac{\left(20-x \right )}{x} = \dfrac{1}{4} \\
& \Rightarrow 80 - 4x = x \\
& \Rightarrow 5x = 80 \nonumber \\
& \Rightarrow x = \dfrac{80}{5} = 16 \\

\end{aligned}

4. The cash difference between the selling prices of an article at a profit of 4% and 6% is Rs 3. The ratio of two selling prices is

51:52
52:53
53:54
54:55

Answer: Option B

Explanation:

Let the Cost price of article is Rs. x

Required ratio =
\begin{aligned}
\frac{104\% \text{ of } x}{106\% \text{ of } x} \\
= \frac{104}{106} = \frac{52}{53} = 52:53
\end{aligned}

5. If the cost price of 12 items is equal to the selling price of 16 items, the loss percent is

Answer: Option B

Explanation:

Let the Cost Price of 1 item = Re. 1
Cost Price of 16 items = 16
Selling Price of 16 items = 12

Loss = 16 - 12 = Rs 4

Loss % = (4/16)* 100 = 25%