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Question Detail
A man is walking at the rate of 5 km/hr crosses a bridge in 15 minutes. The length of the bridge is
- 1000 meters
- 1050 meters
- 1200 meters
- 1250 meters
Answer: Option D
Explanation:
We need to get the answer in meters. So we will first of change distance from km/hour to meter/sec by multiplying it with 5/18 and also change 15 minutes to seconds by multiplying it with 60.
Speed=5∗518=2518m/secTime=15∗60seconds=900secondsDistance=Time∗SpeedDistance=2518∗900=1250meter
1. A man complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km.
- 200 Km
- 222 Km
- 224 Km
- 248 Km
Answer: Option C
Explanation:
Let time taken to travel the first half = x hr
Then time taken to travel the second half = (10 - x) hr
Distance covered in the the first half = 21x [because, distance = time*speed]
Distance covered in the the second half = 24(10 - x)
Distance covered in the the first half = Distance covered in the the second half
So,
21x = 24(10 - x)
=> 45x = 240
=> x = 16/3
Total Distance = 2*21(16/3) = 224 Km [multiplied by 2 as 21x was distance of half way]
2. An athlete runs 200 meters in 24 seconds. His speed is ?
- 10 km/hr
- 17 k/hr
- 27 km/hr
- 30 km/hr
Answer: Option D
Explanation:
Speed=DistanceTime=20024m/sec=253m/sec253∗185km/hr=30km/hr
3. How many minutes does Aditya take to cover a distance of 400 m, if he runs at a speed of 20 km/hr
- 115min
- 215min
- 315min
- 415min
Answer: Option A
Explanation:
We know that,
Time=DistanceSpeedSpeed=20 km/hr=20∗518m/sec=509m/sec Time =(400∗950)=72sec=115min
4. 2 trains starting at the same time from 2 stations 200 km apart and going in opposite direction cross each other at a distance of 110 km from one of the stations. What is the ratio of their speeds ?
- 11:9
- 13:9
- 17:9
- 21:9
Answer: Option A
Explanation:
We know total distance is 200 Km
If both trains crossed each other at a distance of 110 km then one train covered 110 km and other 90 km [110+90=200km]
So ratio of their speed = 110:90 = 11:9
5. A train covers a distance in 50 minutes, if it runs at a speed of 48kmph on an average. Find the speed at which the train must run to reduce the time of journey to 40 minutes.
- 50 km/hr
- 60 km/hr
- 65 km/hr
- 70 km/hr
Answer: Option B
Explanation:
We are having time and speed given, so first we will calculate the distance. Then we can get new speed for given time and distance.
Lets solve it.
Time = 50/60 hr = 5/6 hr
Speed = 48 mph
Distance = S*T = 48 * 5/6 = 40 km
New time will be 40 minutes so,
Time = 40/60 hr = 2/3 hr
Now we know,
Speed = Distance/Time
New speed = 40*3/2 kmph = 60kmph
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