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Question Detail
A man can do a piece of work in 5 days, but with the help of his son he can do it in 3 days. In what time can the son do it alone ?
- \begin{aligned} 7\frac{1}{2}days \end{aligned}
- \begin{aligned} 6\frac{1}{2}days \end{aligned}
- \begin{aligned} 5\frac{1}{2}days \end{aligned}
- \begin{aligned} 4\frac{1}{2}days \end{aligned}
Answer: Option A
Explanation:
In this type of question, where we have one person work and together work done. Then we can easily get the other person work just by subtracting them. As,
Son's one day work =
\begin{aligned}
\left(\frac{1}{3}-\frac{1}{5} \right) \\
=\left(\frac{5-3}{15} \right) \\
= \frac{2}{15}
\end{aligned}
So son will do whole work in 15/2 days
which is =
\begin{aligned} 7\frac{1}{2}days \end{aligned}
1. A is twice as good as workman as B and together they finish a piece of work in 18 days. In how many days will B alone finish the work.
- 27 days
- 54 days
- 56 days
- 68 days
Answer: Option B
Explanation:
As per question, A do twice the work as done by B.
So A:B = 2:1
Also (A+B) one day work = 1/18
To get days in which B will finish the work, lets calculate work done by B in 1 day =
\begin{aligned}
=\left(\frac{1}{18}*\frac{1}{3} \right) \\
= \frac{1}{54}
\end{aligned}
[Please note we multiplied by 1/3 as per B share and total of ratio is 1/3]
So B will finish the work in 54 days
2. A can do a certain job in 25 days which B alone can do in 20 days. A started the work and was joined by B after 10 days. The number of days taken in completing the wotk were ?
- \begin{aligned} 14\frac{2}{3}kmph \end{aligned}
- \begin{aligned} 15\frac{2}{3}kmph \end{aligned}
- \begin{aligned} 16\frac{2}{3}kmph \end{aligned}
- \begin{aligned} 17\frac{2}{3}kmph \end{aligned}
Answer: Option C
Explanation:
Work done by A in l0 days = (1/25) *10 = 2/5
Remaining work = 1 - (2/5) = 3/5
(A+B)s 1 days work = (1/25) + (1/20) = 9/100
9/100 work is done by them in 1 day.
hence 3/5 work will be done by them in (3/5)*(100/9)
= 20/3days.
Total time taken = (10 + 20/3) = 16*(2/3) days
3. A does a work in 10 days and B does the same work in 15 days. In how many days they together will do the same work ?
- 5 days
- 6 days
- 7 days
- 8 days
Answer: Option B
Explanation:
Firstly we will find 1 day work of both A and B, then by adding we can get collective days for them,
So,
A's 1 day work = 1/10
B's 1 day work = 1/15
(A+B)'s 1 day work =
\begin{aligned}
\left(\frac{1}{10}+\frac{1}{15} \right) \\
=\left(\frac{3+2}{30} \right) \\
= \frac{1}{6}
\end{aligned}
So together they can complete work in 6 days.
4. Rahul and Sham together can complete a task in 35 days, but Rahul alone can complete same work in 60 days. Calculate in how many days Sham can complete this work ?
- 84 days
- 82 days
- 76 days
- 68 days
Answer: Option A
Explanation:
As Rahul and Sham together can finish work in 35 days.
1 days work of Rahul and Sham is 1/35
Rahul can alone complete this work in 60 days,
So, Rahul one day work is 1/60
Clearly, Sham one day work will be = (Rahul and Sham one day work) - (Rahul one day work)
\begin{aligned}
= \frac{1}{35} - \frac{1}{60} \\
= \frac{1}{84} \\
\end{aligned}
Hence Sham will complete the given work in 84 days.
5. Worker A takes 8 hours to do a job. Worker B takes 10 hours to do a job. How long should it take both A and B, working together to do same job.
- \begin{aligned} \frac{4}{9} \end{aligned}
- \begin{aligned} 2\frac{4}{9} \end{aligned}
- \begin{aligned} 3\frac{4}{9} \end{aligned}
- \begin{aligned} 4\frac{4}{9} \end{aligned}
Answer: Option D
Explanation:
In this type of questions, first we need to calculate 1 hours work, then their collective work as,
A's 1 hour work is 1/8
B's 1 hour work is 1/10
(A+B)'s 1 hour work = 1/8 + 1/10
= 9/40
So both will finish the work in 40/9 hours
= \begin{aligned} 4\frac{4}{9} \end{aligned}
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