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Question Detail
A library has an average of 510 visitors on Sundays and 240 on other day. The average number of visitors in a month of 30 days starting with sunday is
- 280
- 285
- 290
- 295
Answer: Option B
Explanation:
As the month begin with sunday, so there will be five sundays in the month. So result will be:
\begin{aligned}
= (\frac{510 \times 5 + 240 \times 25}{30})
= (\frac{8550}{30}) = 285
\end{aligned}
1. When a student weighing 45 kgs left a class, the average weight of the remaining 59 students increased by 200g. What is the average weight of the remaining 59 students
- 55
- 56
- 57
- 58
Answer: Option C
Explanation:
Let the average weight of the 59 students be A.
So the total weight of the 59 of them will be 59*A.
The questions states that when the weight of this student who left is added, the total weight of the class = 59A + 45
When this student is also included, the average weight decreases by 0.2 kgs
\begin{aligned}
\frac{59A + 45}{60} = A - 0.2
\end{aligned}
=> 59A + 45 = 60A - 12
=> 45 + 12 = 60A - 59A
=> A = 57
2. Find the average of first 10 multiples of 7
- 35.5
- 37.5
- 38.5
- 40.5
Answer: Option C
Explanation:
\begin{aligned}
= \frac {7(1+2+3+...+10)}{10}
\end{aligned}
\begin{aligned}
= \frac {7(10(10+1))}{10 \times 2}
\end{aligned}
\begin{aligned}
= \frac {7(110)}{10 \times 2} = 38.5
\end{aligned}
3. If the average marks of three batches of 55, 60 and 45 students respectively is 50, 55, 60, then the average marks of all the students is
- 54.48
- 54.68
- 54.60
- 54.58
Answer: Option B
Explanation:
\begin{aligned}
\frac{(55 \times 50) +(60 \times 55) +(45 \times 60) }{55 + 60 + 45}
\end{aligned}
\begin{aligned}
\frac{8750}{160} = 54.68
\end{aligned}
4. The average of four consecutive odd numbers is 24. Find the largest number.
- 25
- 27
- 29
- 31
Answer: Option B
Explanation:
Let the numbers are x, x+2, x+4, x+6, then
\begin{aligned}
=> \frac{x+(x+2)+(x+4)+(x+6)}{4} = 24
\end{aligned}
\begin{aligned}
=> \frac{4x+12)}{4} = 24
\end{aligned}
\begin{aligned}
=> x+3 = 24 => x = 21
\end{aligned}
So largest number is 21 + 6 = 27
5. The average of six numbers is X and the average of three of these is Y.If the average of the remaining three is z, then
- x = y + z
- 2x = y + z
- x = 2y + z
- x = y + 2z
Answer: Option B
Explanation:
X =((3y+3z)/6)
or
2X= y + z
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