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A dog takes 3 leaps for every 5 leaps of a hare. If one leap of the dog is equal to 3 leaps of the hare, the ratio of the speed of the dog to that of the hare is

  • 4:5
  • 9:5
  • 8:5
  • 9:2
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2. If A:B = 2:3, B:C = 4:5 and C:D = 6:7, then find the value of A:B:C:D

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3. The least whole number which when subtracted from both the terms of the ratio 6 : 7 to give a ratio less than 16 : 21, is

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5. If 2 : 9 :: x : 18, then find the value of x

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  • sara 11 years ago

    nice n tricky