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A can do a piece of work in 15 days and B alone can do it in 10 days. B works at it for 5 days and then leaves. A alone can finish the remaining work in

  • 5 days
  • 6 days
  • 7.5 days
  • 8.5 days
Similar Questions :

1. A can do a certain job in 25 days which B alone can do in 20 days. A started the work and was joined by B after 10 days. The number of days taken in completing the wotk were ?

  • \begin{aligned} 14\frac{2}{3}kmph \end{aligned}
  • \begin{aligned} 15\frac{2}{3}kmph \end{aligned}
  • \begin{aligned} 16\frac{2}{3}kmph \end{aligned}
  • \begin{aligned} 17\frac{2}{3}kmph \end{aligned}

2. To complete a work A and B takes 8 days, B and C takes 12 days, A,B and C takes 6 days. How much time A and C will take

  • 24 days
  • 16 days
  • 12 days
  • 8 days

3. A can do a piece of work in 4 hours . A and C together can do it in just 2 hours, while B and C together need 3 hours to finish the same work. In how many hours B can complete the work ?

  • 10 hours
  • 12 hours
  • 16 hours
  • 18 hours

4. A completes 80% of a work in 20 days. Then B also joins and A and B together finish the remaining work in 3 days. How long does it need for B if he alone completes the work?

  • \begin{aligned} 35\frac{1}{2} \end{aligned}
  • \begin{aligned} 36\frac{1}{2} \end{aligned}
  • \begin{aligned} 37\frac{1}{2} \end{aligned}
  • \begin{aligned} 38\frac{1}{2} \end{aligned}

5. A tyre has two punctures. The first puncture alone would have made the tyre flat in 9 minutes and the second alone would have done it in 6 minutes. If air leaks out at a constant rate, how long does it take both the punctures together to make it flat ?

  • \begin{aligned} 3\frac{1}{5} min \end{aligned}
  • \begin{aligned} 3\frac{2}{5} min \end{aligned}
  • \begin{aligned} 3\frac{3}{5} min \end{aligned}
  • \begin{aligned} 3\frac{4}{5} min \end{aligned}
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