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Question Detail
A can do a job in 16 days, B can do same job in 12 days. With the help of C they did the job in 4 days. C alone can do the same job in how many days ?
- 612days
- 712days
- 835days
- 935days
Answer: Option D
Explanation:
In this question we having, A's work, B's work and A+B+C work. We need to calculate C's work.
We can do it by,
(A+B+C)'s work - (A's work + B's work).
Let's solve it now:
C's 1 day work =
14−(116+112)=(14−748)=548
So C can alone finish the job in 48/5 days,
Which is =
935days
1. A alone can do a piece of work in 6 days and B alone in 8 days. A and B undertook to do it for Rs. 3200. With the help of C, they completed the work in 3 days. How much is to be paid to C
- Rs. 300
- Rs. 400
- Rs. 500
- Rs. 600
Answer: Option B
Explanation:
C's 1 day's work =
13−(16+18)=(13−724)=124A:B:C=16:18:124=4:3:1C′sShare=18∗3200=400
If you are confused how we multiplied 1/8, then please study ratio and proportion chapter, for small information, it is the C ratio divided by total ratio.
2. A and B can together complete a piece of work in 4 days. If A alone can complete the same work in 12 days, in how many days can B alone complete that work ?
- 4 days
- 5 days
- 6 days
- 7 days
Answer: Option C
Explanation:
(A+B)'s 1 day work = 1/4
A's 1 day work = 1/12
B's 1 day work =
(14−112)=3−112=16
So B alone can complete the work in 6 days
3. A tyre has two punctures. The first puncture alone would have made the tyre flat in 9 minutes and the second alone would have done it in 6 minutes. If air leaks out at a constant rate, how long does it take both the punctures together to make it flat ?
- 315min
- 325min
- 335min
- 345min
Answer: Option C
Explanation:
Do not be confused, Take this question same as that of work done question's. Like work done by 1st puncture in 1 minute and by second in 1 minute.
Lets Solve it:
1 minute work done by both the punctures =
(19+16)=(518)
So both punctures will make the type flat in
(185)mins=335mins
4. To complete a work A and B takes 8 days, B and C takes 12 days, A,B and C takes 6 days. How much time A and C will take
- 24 days
- 16 days
- 12 days
- 8 days
Answer: Option D
Explanation:
A+B 1 day work = 1/8
B+C 1 day work = 1/12
A+B+C 1 day work = 1/6
We can get A work by (A+B+C)-(B+C)
And C by (A+B+C)-(A+B)
So A 1 day work =
16−112=112
Similarly C 1 day work =
16−18=4−324=124
So A and C 1 day work =
112+124=324=18
So A and C can together do this work in 8 days
5. A does half as much work as B in three-fourth of the time. If together they take 18 days to complete the work, how much time shall B take to do it
- 40 days
- 35 days
- 30 days
- 25 days
Answer: Option C
Explanation:
Suppose B takes x dáys to do the work.
As per question A will take
2∗34∗x=3x2days
(A+B)s 1 days work= 1/18
1/x + 2/3x = 1/18 or x = 30 days
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