- Home
- Quantitative
- English
- Reasoning
- IT Officer
- Programming
-
Computer
- Computer Awareness Questions Answers - Set 1
- Computer Awareness Questions Answers - Set 2
- Important Abbreviations Computer Awareness Questions Answers
- Important File Extensions Questions Answers
- Computer System Architecture Questions Answers
- MS Office Questions Answers
- MS Excel Questions Answers
- MS PowerPoint Questions Answers
-
GK
- Geography Questions Answers
- Indian History Questions Answers
- World History Questions Answers
- Indian Economy Questions Answers
- Indian Polity and Constitution
- Physics Questions Answers
- Chemistry Questions Answers
- Biology Questions Answers
- First In India
- First In World
- Longest and Largest
- Books and Authors
- Important Days of year
- Countries and Capitals
- Inventions and Inventors
-
Current Affairs
- Current Affairs
- Current Affairs 2018
- Current Affairs 2018 - 2019 PDF
- Current Affairs August 2019
- Current Affairs July 2019
- Current Affairs June 2019
- Current Affairs May 2019
- Current Affairs April 2019
- Current Affairs March 2019
- Current Affairs February 2019
- Current Affairs January 2019
- Current Affairs December 2018
- Current Affairs November 2018
- Current Affairs October 2018
- Current Affairs September 2018
- Govt Jobs
- Exams
- Online Quiz
- You are here
- Home
- Quantitative Aptitude
- Arithmetic Aptitude Questions Answers
- Time and Work Questions Answers
- Aptitude Question
- Current Affairs 2019
- Current Affairs 2018
- Current Affairs December 2018
- Current Affairs November 2018
- Current Affairs October 2018
- Current Affairs September 2018
- Current Affairs August 2018
- Current Affairs July 2018
- Current Affairs June 2018
- Current Affairs May 2018
- Current Affairs April 2018
- Current Affairs March 2018
- Current Affairs February 2018
- Current Affairs January 2018
- Current Affairs 2018
- Current Affairs PDF
- Current Affairs PDF Download
- Current Affairs July 2019 PDF
- Current Affairs June 2019 PDF
- Current Affairs May 2019 PDF
- Current Affairs April 2019 PDF
- Current Affairs March 2019 PDF
- Current Affairs February 2019 PDF
- Current Affairs January 2019 PDF
- Current Affairs December 2018 PDF
- Current Affairs November 2018 PDF
- Current Affairs October 2018 PDF
- Current Affairs September 2018 PDF
- Current Affairs August 2018 PDF
- Current Affairs July 2018 PDF
- Current Affairs June 2018 PDF
- Current Affairs May 2018 PDF
- Current Affairs April 2018 PDF
- Current Affairs March 2018 PDF
- Current Affairs February 2018 PDF
- Current Affairs January 2018 PDF
Question Detail
A can do a job in 16 days, B can do same job in 12 days. With the help of C they did the job in 4 days. C alone can do the same job in how many days ?
- \begin{aligned} 6\frac{1}{2}days \end{aligned}
- \begin{aligned} 7\frac{1}{2}days \end{aligned}
- \begin{aligned} 8\frac{3}{5}days \end{aligned}
- \begin{aligned} 9\frac{3}{5}days \end{aligned}
Answer: Option D
Explanation:
In this question we having, A's work, B's work and A+B+C work. We need to calculate C's work.
We can do it by,
(A+B+C)'s work - (A's work + B's work).
Let's solve it now:
C's 1 day work =
\begin{aligned}
\frac{1}{4}- \left(\frac{1}{16} +\frac{1}{12} \right) \\
=\left(\frac{1}{4} - \frac{7}{48} \right) \\
= \frac{5}{48}
\end{aligned}
So C can alone finish the job in 48/5 days,
Which is =
\begin{aligned} 9\frac{3}{5}days \end{aligned}
1. A completes 80% of a work in 20 days. Then B also joins and A and B together finish the remaining work in 3 days. How long does it need for B if he alone completes the work?
- \begin{aligned} 35\frac{1}{2} \end{aligned}
- \begin{aligned} 36\frac{1}{2} \end{aligned}
- \begin{aligned} 37\frac{1}{2} \end{aligned}
- \begin{aligned} 38\frac{1}{2} \end{aligned}
Answer: Option C
Explanation:
Work done by A in 20 days = 80/100 = 8/10 = 4/5
Work done by A in 1 day = (4/5) / 20 = 4/100 = 1/25 --- (1)
Work done by A and B in 3 days = 20/100 = 1/5 (Because remaining 20% is done in 3 days by A and B)
Work done by A and B in 1 day = 1/15 ---(2)
Work done by B in 1 day = 1/15 – 1/25 = 2/75
=> B can complete the work in 75/2 days = 37 (1/2) days
2. 5 men and 2 boys working together can do four times as much work as a man and a boy. Working capacity of man and boy is in the ratio
- 1:2
- 1:3
- 2:1
- 2:3
Answer: Option C
Explanation:
Let 1 man 1 day work = x
1 boy 1 day work = y
then 5x + 2y = 4(x+y)
=> x = 2y
=> x/y = 2/1
=> x:y = 2:1
3. A alone can complete a work in 16 days and B alone can do in 12 days. Starting with A, they work on alternate days. The total work will be completed in
- \begin{aligned} 13\frac{1}{4} \end{aligned}
- \begin{aligned} 13\frac{1}{2} \end{aligned}
- \begin{aligned} 13\frac{3}{4} \end{aligned}
- \begin{aligned} 13\frac{4}{4} \end{aligned}
Answer: Option C
Explanation:
A's 1 day work = 1/16
B's 1 day work = 1/12
As they are working on alternate day's
So their 2 days work = (1/16)+(1/12)
= 7/48
[here is a small technique, Total work done will be 1, right, then multiply numerator till denominator, as 7*6 = 42, 7*7 = 49, as 7*7 is more than 48, so we will consider 7*6, means 6 pairs ]
Work done in 6 pairs = 6*(7/48) = 7/8
Remaining work = 1-7/8 = 1/8
On 13th day it will A turn,
then remaining work = (1/8)-(1/16) = 1/16
On 14th day it is B turn,
1/12 work done by B in 1 day
1/16 work will be done in (12*1/16) = 3/4 day
So total days =
\begin{aligned} 13\frac{3}{4} \end{aligned}
It may be a bit typical question, but if are not getting it in first try then give it a second try. Even not, then comment for explanation for this. We will be happy to help you.
4. A tyre has two punctures. The first puncture alone would have made the tyre flat in 9 minutes and the second alone would have done it in 6 minutes. If air leaks out at a constant rate, how long does it take both the punctures together to make it flat ?
- \begin{aligned} 3\frac{1}{5} min \end{aligned}
- \begin{aligned} 3\frac{2}{5} min \end{aligned}
- \begin{aligned} 3\frac{3}{5} min \end{aligned}
- \begin{aligned} 3\frac{4}{5} min \end{aligned}
Answer: Option C
Explanation:
Do not be confused, Take this question same as that of work done question's. Like work done by 1st puncture in 1 minute and by second in 1 minute.
Lets Solve it:
1 minute work done by both the punctures =
\begin{aligned}
\left(\frac{1}{9}+\frac{1}{6} \right) \\
=\left(\frac{5}{18} \right) \\
\end{aligned}
So both punctures will make the type flat in
\begin{aligned}
\left(\frac{18}{5} \right)mins \\
= 3\frac{3}{5} mins
\end{aligned}
5. To complete a work A and B takes 8 days, B and C takes 12 days, A,B and C takes 6 days. How much time A and C will take
- 24 days
- 16 days
- 12 days
- 8 days
Answer: Option D
Explanation:
A+B 1 day work = 1/8
B+C 1 day work = 1/12
A+B+C 1 day work = 1/6
We can get A work by (A+B+C)-(B+C)
And C by (A+B+C)-(A+B)
So A 1 day work =
\begin{aligned}
\frac{1}{6}- \frac{1}{12} \\
= \frac{1}{12}
\end{aligned}
Similarly C 1 day work =
\begin{aligned}
\frac{1}{6}- \frac{1}{8} \\
= \frac{4-3}{24} \\
= \frac{1}{24}
\end{aligned}
So A and C 1 day work =
\begin{aligned}
\frac{1}{12} + \frac{1}{24} \\
= \frac{3}{24} \\
= \frac{1}{8}
\end{aligned}
So A and C can together do this work in 8 days
Thanks ! Your comment will be approved shortly !
- Copyright 2014 - All rights reserved
- Terms Of Use & Privacy Policy
- Contact Us
- Copyright