Question Detail
A, B, C and D play a game of cards. A says to B. "If I give you 8 cards, you will have as many as C has and I shall have 3 less than what C has. Also if I take 8 cards from C, I shall have twice as many as D has." If B and D together have 50 cards, how many cards have A got?
- 35
- 37
- 38
- 40
Answer: Option D
Explanation:
If we read given question carefully, we get,
B+8 = C ---(i)
A-8 = C-3 ---(ii)
A+6 = 2D ---(iii)
B+D = 50 ---(iv)
Putting C = A -5 from (ii) into (i), we have :
B+8 = A-5 or A-B = 13 ---(v)
Putting D = 50-B from (iv) and (iii), we have :
A+6 = 100-2B or A+2B = 94 ---(vi)
Solving (v) and (vi), we get
B = 27 and A = 40
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Parampreet Singh 9 years ago
how yiu generated A+6=2d it should be A+8=2d
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