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Question Detail
a * b = 2a - 3b + ab, then 3*5 + 5*3 = ?
- 20
- 21
- 22
- 23
Answer: Option C
Explanation:
= 2(3)-3(5)+(3*5) + 2(5)-3(3)+(5*3)
= 6-15+15+10-9+15 = 31-9 = 22
1. Value of
\begin{aligned}
\frac{1}{2+\frac{1}{2+\frac{1}{2-\frac{1}{2}}}}
\end{aligned}
- \begin{aligned} \frac{6}{19} \end{aligned}
- \begin{aligned} \frac{7}{19} \end{aligned}
- \begin{aligned} \frac{8}{19} \end{aligned}
- \begin{aligned} \frac{9}{19} \end{aligned}
Answer: Option C
Explanation:
\begin{aligned}
= \frac{1}{2+\frac{1}{2+\frac{1}{\frac{3}{2}}}}
\end{aligned}
\begin{aligned}
= \frac{1}{2+\frac{1}{2+\frac{2}{3}}}
\end{aligned}
\begin{aligned}
= \frac{1}{2+\frac{1}{\frac{8}{3}}}
\end{aligned}
\begin{aligned}
= \frac{1}{2+\frac{3}{8}}
\end{aligned}
\begin{aligned}
= \frac{1}{\frac{19}{8}}
\end{aligned}
\begin{aligned}
= \frac{8}{19}
\end{aligned}
2. In a class free notebooks were distributed among all the children. Each child got notebooks which were one-eighth of the number of children. If number of children been half, then each child would have recieved 16 notebooks in total. Find the total number of books distributed.
- 450
- 512
- 598
- 658
Answer: Option B
Explanation:
Let suppose total number of students in class are X.
Then from the question we can conclude it that,
\begin{aligned}
X*\frac{1}{8}X = \frac{X}{2}*16 \\
=> X = 64\\
\text{Total notebooks,} \\
= \frac{1}{8}X^2 \\
= \left( \frac{1}{8} * 64 * 64 \right) \\
= 512
\end{aligned}
3. 100 + 50 * 2 = ?
- 200
- 150
- 100
- 300
Answer: Option A
Explanation:
After applying BOMAS rule,
First Multiplication will be done then addition
So it will be 100 + 100 = 200
4. 18800 / 470 / 20
- 1
- 2
- 3
- 4
Answer: Option B
Explanation:
18800 / 470 / 20 = (18800 / 470) / 20 = 40 / 20 = 2
5. a * b = 2a - 3b + ab, then 3*5 + 5*3 = ?
- 20
- 21
- 22
- 23
Answer: Option C
Explanation:
= 2(3)-3(5)+(3*5) + 2(5)-3(3)+(5*3)
= 6-15+15+10-9+15 = 31-9 = 22
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