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Question Detail
A alone can do a piece of work in 6 days and B alone in 8 days. A and B undertook to do it for Rs. 3200. With the help of C, they completed the work in 3 days. How much is to be paid to C
- Rs. 300
- Rs. 400
- Rs. 500
- Rs. 600
Answer: Option B
Explanation:
C's 1 day's work =
\begin{aligned}
\frac{1}{3}- \left(\frac{1}{6} +\frac{1}{8} \right) \\
=\left(\frac{1}{3} - \frac{7}{24} \right) \\
= \frac{1}{24} \\
A:B:C = \frac{1}{6}:\frac{1}{8}:\frac{1}{24} \\
= 4:3:1 \\
C's Share = \frac{1}{8}* 3200 \\
= 400
\end{aligned}
If you are confused how we multiplied 1/8, then please study ratio and proportion chapter, for small information, it is the C ratio divided by total ratio.
1. A and B can together complete a piece of work in 4 days. If A alone can complete the same work in 12 days, in how many days can B alone complete that work ?
- 4 days
- 5 days
- 6 days
- 7 days
Answer: Option C
Explanation:
(A+B)'s 1 day work = 1/4
A's 1 day work = 1/12
B's 1 day work =
\begin{aligned}
\left( \frac{1}{4} - \frac{1}{12} \right) \\
= \frac{3-1}{12} \\
= \frac{1}{6} \\
\end{aligned}
So B alone can complete the work in 6 days
2. A does half as much work as B in three-fourth of the time. If together they take 18 days to complete the work, how much time shall B take to do it
- 40 days
- 35 days
- 30 days
- 25 days
Answer: Option C
Explanation:
Suppose B takes x dáys to do the work.
As per question A will take
\begin{aligned}
2* \frac{3}{4} * x = \frac{3x}{2}days
\end{aligned}
(A+B)s 1 days work= 1/18
1/x + 2/3x = 1/18 or x = 30 days
3. A completes 80% of a work in 20 days. Then B also joins and A and B together finish the remaining work in 3 days. How long does it need for B if he alone completes the work?
- \begin{aligned} 35\frac{1}{2} \end{aligned}
- \begin{aligned} 36\frac{1}{2} \end{aligned}
- \begin{aligned} 37\frac{1}{2} \end{aligned}
- \begin{aligned} 38\frac{1}{2} \end{aligned}
Answer: Option C
Explanation:
Work done by A in 20 days = 80/100 = 8/10 = 4/5
Work done by A in 1 day = (4/5) / 20 = 4/100 = 1/25 --- (1)
Work done by A and B in 3 days = 20/100 = 1/5 (Because remaining 20% is done in 3 days by A and B)
Work done by A and B in 1 day = 1/15 ---(2)
Work done by B in 1 day = 1/15 – 1/25 = 2/75
=> B can complete the work in 75/2 days = 37 (1/2) days
4. A man can do a piece of work in 5 days, but with the help of his son he can do it in 3 days. In what time can the son do it alone ?
- \begin{aligned} 7\frac{1}{2}days \end{aligned}
- \begin{aligned} 6\frac{1}{2}days \end{aligned}
- \begin{aligned} 5\frac{1}{2}days \end{aligned}
- \begin{aligned} 4\frac{1}{2}days \end{aligned}
Answer: Option A
Explanation:
In this type of question, where we have one person work and together work done. Then we can easily get the other person work just by subtracting them. As,
Son's one day work =
\begin{aligned}
\left(\frac{1}{3}-\frac{1}{5} \right) \\
=\left(\frac{5-3}{15} \right) \\
= \frac{2}{15}
\end{aligned}
So son will do whole work in 15/2 days
which is =
\begin{aligned} 7\frac{1}{2}days \end{aligned}
5. A can do a piece of work in 15 days and B alone can do it in 10 days. B works at it for 5 days and then leaves. A alone can finish the remaining work in
- 5 days
- 6 days
- 7.5 days
- 8.5 days
Answer: Option C
Explanation:
B's 5 days work =
\begin{aligned}
\frac{1}{10}*5 = \frac{1}{2} \\
\text{Remaining work =} 1-\frac{1}{2} \\
= \frac{1}{2} \\
\text{A can finish work =}15*\frac{1}{2} \\
= 7.5 days
\end{aligned}
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