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Question Detail
A 300 meter long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform.
- 310 meter
- 335 meter
- 345 meter
- 350 meter
Answer: Option D
Explanation:
Speed = Distance/time = 300/18 = 50/3 m/sec
Let the length of the platform be x meters
then
Distance=Speed∗Timex+300=503∗39=>3(x+300)=1950=>x=350 meters
1. A train is 100 meter long and is running at the speed of 30 km per hour. Find the time it will take to pass a man standing at a crossing.
- 10 seconds
- 12 seconds
- 14 seconds
- 16 seconds
Answer: Option B
Explanation:
As we need to get answer in seconds, so never forget to convert speed into meter per second.
Speed = 30 km/hr = 30* 5/18 m/sec
= 25/3 m/sec
Distance = length of train = 100 meter
Required time =
DistanceSpeed=100253=100∗325=12sec
2. A jogger running at 9 kmph alongside a railway track is 240 metres ahead of the engine of a 120 metre long train running at 45 kmph in the same direction. In how much time will the train pass the jogger ?
- 30 seconds
- 32 seconds
- 34 seconds
- 36 seconds
Answer: Option D
Explanation:
Speed of train relative to jogger = (45-9) = 36 kmph
= 36*(5/18) = 10 m/sec
Distance to cover = 240 + 120 = 360 metres
Time = Distance/Speed
So,
Time=36010=36 Seconds
3. A train is running with a speed of 60 kmph and its length is 110 metres. Calculate the time by which it will pass a man running opposite with speed of 6 kmph.
- 2 second
- 4 second
- 6 second
- 8 second
Answer: Option C
Explanation:
From the given question,
we will first calculate the speed of train relative to man,
=> ( 60 + 6 ) = 66 km/hr ( we added 6 because man is running opposite )
Convert it in metre/second
=66×518=553m/secTime it will take to pass man =110×355=6 seconds
4. A train, 800 meter long is running with a speed of 78 km/hr. It crosses a tunnel in 1 minute. What is the length of the tunnel ?
- 650 meter
- 555 meter
- 500 meter
- 458 meter
Answer: Option C
Explanation:
Let length of tunnel is x meter
Distance = 800+x meter
Time = 1 minute = 60 seconds
Speed = 78 km/hr = 78*5/18 m/s = 65/3 m/s
Distance = Speed*Time
=>800+x=653∗60=>800+x=20∗65=1300=>x=1300−800=500
So the length of the tunnel is 500 meters.
[If you want to calculate it practically, then please have your copy and pen and take a ride of Kalka to Shimla toy train in north India. It has many tunnels on the way :) ]
5. A train overtakes two persons who are walking in the same direction in which the train is going, at the rate of 2 kmph and 4 kmph and passes them completely in 9 and 10 seconds respectively. Find the length of train ?
- 45 m
- 50 m
- 55 m
- 60 m
Answer: Option B
Explanation:
First person speed = 2*(5/18) = 5/9 m/sec
Second person speed = 4*(5/18) = 10/9 m/sec
Let the length of train is x metre and speed is y m/sec
then,
xy−59=9=>9y−5=x=>9y−x=5.....(i)Also,xy−109=1090y−9x=100.....(ii)from (i) and (ii), we get,x=50
So length of train is 50 metre
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