2. Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are
42,30
42,31
42,32
42,33
Answer: Option D
Explanation:
Let their marks be (x+9) and x.
Then, x+9 = 56/100(x + 9 +x)
=> 25(x+9)
=> 14 (2x + 9)
=> 3x = 99
=> x = 33.
So, their marks are 42 and 33
3. 1/2 is what percent of 1/3
150%
200%
250%
300%
Answer: Option A
Explanation:
1/2/1/3 * 100 = 1/2 * 3/1 * 100 = 150 %
4. A student multiplied a number by 3/5 instead of 5/3. What is the percentage error.
64%
65%
66%
67%
Answer: Option A
Explanation:
Let the number be x,
then,
\begin{aligned}
\frac{5}{3} - \frac{3}{5} = \frac{16}{15}x
\end{aligned}