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Question Detail
7589 - X = 3434
- 4155
- 2321
- 3155
- None of above
Answer: Option A
1. What is the unit digit in
(6324)1797×(615)316×(341)476
- 1
- 5
- 7
- 0
Answer: Option D
2. What least number should be added to 1056, so that the sum is completely divisible by 23
- 4
- 1
- 2
- 3
Answer: Option C
Explanation:
(1056 / 23) gives remainder 21
21 + 2 = 23, So we need to add 2
3. What least number must be subtracted from 427398 so that remaining number is divisible by 15
- 3
- 5
- 7
- 9
Answer: Option A
Explanation:
On dividing 427398 by 15 we get the remainder 3, so 3 should be subtracted
4. What least value should be replaced by * in 223*431 so the number become divisible by 9
- 3
- 4
- 5
- 6
Answer: Option A
Explanation:
Trick: Number is divisible by 9, if sum of all digits is divisible by 9, so (2+2+3+*+4+3+1) = 15+* should be divisible by 9,
15+3 will be divisible by 9,
so that least number is 3.
5. 217 * 217 + 183 * 183
- 70578
- 82578
- 80578
- 80568
Answer: Option C
Explanation:
12×2(a2+b2)=12×[(a+b)2+(a−b)2]
=12×[(217+183)2+(217−183)2]=80578
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