Question Detail

5.8 * 2.5 + 0.6 * 6.75 + 139.25= ?

157.60
147.80
147.60
157.80

Answer: Option D

1. Along a yard 225 metres long, 26 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between two consecutive trees

Answer: Option B

Explanation:

26 trees have 25 gaps between them,
Required distance (225/25) = 10

2. $\begin{aligned} 3034 -(1002 \div 20.04) = ? \end{aligned}$

1964
1984
2964
2984

Answer: Option D

Explanation:

$\begin{aligned} = 3034 -( \frac{1002}{2004} \times 100) \end{aligned}$

$\begin{aligned} = 3034 - 50 = 2984 \end{aligned}$

3. Find the value of X
X = (6/119) * (63/8) * (17/9)

Answer: Option C

4. If p - q = 3 and
$\begin{aligned} p^2 + q^2 = 29 \end{aligned}$ , find the value of pq.

Answer: Option D

Explanation:

We know

$\begin{aligned} 2ab = (a^2 + b^2) - (a - b)^2 \end{aligned}$

$\begin{aligned} 2pq = 29 - 9 = 20 \end{aligned}$

$\begin{aligned} =>pq = 10 \end{aligned}$

5. $\begin{aligned} (3\frac{1}{4}\div \{1\frac{1}{4} - \frac{1}{2}(2\frac{1}{2} - \overline {\frac{1}{4} - \frac{1}{6}} ) \} ) \end{aligned}$

Answer: Option A

Explanation:

Tip:
As you can see, there is bar over

$\begin{aligned} \overline{\frac{1}{4}-\frac{1}{6}} \end{aligned}$
So their sign will be changed from - to + as

$\begin{aligned} \frac{1}{4}+\frac{1}{6} \end{aligned}$

Question Detail

5.8 * 2.5 + 0.6 * 6.75 + 139.25= ?

1. Along a yard 225 metres long, 26 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between two consecutive trees

2. $\begin{aligned} 3034 -(1002 \div 20.04) = ? \end{aligned}$

3. Find the value of X
X = (6/119) * (63/8) * (17/9)

4. If p - q = 3 and
$\begin{aligned} p^2 + q^2 = 29 \end{aligned}$ , find the value of pq.

5. $\begin{aligned} (3\frac{1}{4}\div \{1\frac{1}{4} - \frac{1}{2}(2\frac{1}{2} - \overline {\frac{1}{4} - \frac{1}{6}} ) \} ) \end{aligned}$

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Question Detail

5.8 * 2.5 + 0.6 * 6.75 + 139.25= ?

1. Along a yard 225 metres long, 26 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between two consecutive trees

2. 3034−(1002÷20.04)=?\begin{aligned} 3034 -(1002 \div 20.04) = ? \end{aligned}

3. Find the value of X X = (6/119) * (63/8) * (17/9)

4. If p - q = 3 and p2+q2=29\begin{aligned} p^2 + q^2 = 29 \end{aligned}, find the value of pq.

5. (314÷{114−12(212−¯14−16)})\begin{aligned} (3\frac{1}{4}\div \{1\frac{1}{4} - \frac{1}{2}(2\frac{1}{2} - \overline {\frac{1}{4} - \frac{1}{6}} ) \} ) \end{aligned}

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2. $\begin{aligned} 3034 -(1002 \div 20.04) = ? \end{aligned}$

3. Find the value of X
X = (6/119) * (63/8) * (17/9)

4. If p - q = 3 and
$\begin{aligned} p^2 + q^2 = 29 \end{aligned}$ , find the value of pq.

5. $\begin{aligned} (3\frac{1}{4}\div \{1\frac{1}{4} - \frac{1}{2}(2\frac{1}{2} - \overline {\frac{1}{4} - \frac{1}{6}} ) \} ) \end{aligned}$