Question Detail
5 men and 2 boys working together can do four times as much work as a man and a boy. Working capacity of man and boy is in the ratio
- 1:2
- 1:3
- 2:1
- 2:3
Answer: Option C
Explanation:
Let 1 man 1 day work = x
1 boy 1 day work = y
then 5x + 2y = 4(x+y)
=> x = 2y
=> x/y = 2/1
=> x:y = 2:1
1. A can finish a work in 18 days and B can do same work in half the time taken by A. then working together, what part of same work they can finish in a day
- 1\5
- 1\6
- 1\7
- 1\8
Answer: Option B
Explanation:
Please note in this question, we need to answer part of work for a day rather than complete work. It was worth mentioning here because many do mistake at this point in hurry to solve the question
So lets solve now,
A's 1 day work = 1/18
B's 1 day work = 1/9 [because B take half time than A]
(A+B)'s one day work =
\begin{aligned}
\left(\frac{1}{18}+\frac{1}{9} \right) \\
=\left(\frac{1+2}{18} \right) \\
= \frac{1}{6}
\end{aligned}
So in one day 1/6 work will be done.
2. A is twice as good as workman as B and together they finish a piece of work in 18 days. In how many days will B alone finish the work.
- 27 days
- 54 days
- 56 days
- 68 days
Answer: Option B
Explanation:
As per question, A do twice the work as done by B.
So A:B = 2:1
Also (A+B) one day work = 1/18
To get days in which B will finish the work, lets calculate work done by B in 1 day =
\begin{aligned}
=\left(\frac{1}{18}*\frac{1}{3} \right) \\
= \frac{1}{54}
\end{aligned}
[Please note we multiplied by 1/3 as per B share and total of ratio is 1/3]
So B will finish the work in 54 days
3. 5 men and 2 boys working together can do four times as much work as a man and a boy. Working capacity of man and boy is in the ratio
- 1:2
- 1:3
- 2:1
- 2:3
Answer: Option C
Explanation:
Let 1 man 1 day work = x
1 boy 1 day work = y
then 5x + 2y = 4(x+y)
=> x = 2y
=> x/y = 2/1
=> x:y = 2:1
4. A completes 80% of a work in 20 days. Then B also joins and A and B together finish the remaining work in 3 days. How long does it need for B if he alone completes the work?
- \begin{aligned} 35\frac{1}{2} \end{aligned}
- \begin{aligned} 36\frac{1}{2} \end{aligned}
- \begin{aligned} 37\frac{1}{2} \end{aligned}
- \begin{aligned} 38\frac{1}{2} \end{aligned}
Answer: Option C
Explanation:
Work done by A in 20 days = 80/100 = 8/10 = 4/5
Work done by A in 1 day = (4/5) / 20 = 4/100 = 1/25 --- (1)
Work done by A and B in 3 days = 20/100 = 1/5 (Because remaining 20% is done in 3 days by A and B)
Work done by A and B in 1 day = 1/15 ---(2)
Work done by B in 1 day = 1/15 – 1/25 = 2/75
=> B can complete the work in 75/2 days = 37 (1/2) days
5. 10 women can complete a work in 7 days and 10 children take 14 days to complete the work. How many days will 5 women and 10 children take to complete the work?
- 6 days
- 7 days
- 8 days
- 9 days
Answer: Option B
Explanation:
1 woman's 1 day's work = 1/70
1 Child's 1 day's work = 1/140
5 Women and 10 children 1 day work =
\begin{aligned}
\left(\frac{5}{70}+\frac{10}{140}\right) \\
= \frac{1}{7}
\end{aligned}
So 5 women and 10 children will finish the work in 7 days.